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bekas [8.4K]
3 years ago
9

Increasing the amount of current flowing through a wire strengthens

Chemistry
1 answer:
vagabundo [1.1K]3 years ago
8 0

Answer:

It will strengthen Electromagnetism

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If 1.6 moles of an ideal gas are at a temperature of 25c and a pressure of 0.91 atm hg, what volume would the gas occupy, in lit
Fiesta28 [93]
From\ Ideal\ Gas\ Law:\\\\PV=nRT\\\\
P-pressure\\V-volume\\n-number\ of\ moles\\R- universal\ gas\ constant\\T-absolute\ tmeperature\\\\
R=\ 8,3145J/ mol\ K\\P=0,91atm\\
n=1,6moles\\T=25c\\\\
Converting\ units:\\\\
1atm=101,3kPa=101,3*10^3\\
0,91atm=0,91*101,3*10^3=92,183*10^3Pa\\T=25c=273+25=298K\\\\
V=\frac{nRT}{P}=\frac{1,6*8,3145*298}{92183}=0,043m^3=43liters\\\\Answer\ is\ 43\ liters.
8 0
3 years ago
Cuál es el volumen ocupado por 1000 g de aluminio​
rosijanka [135]

Answer:

No se pues carnal preguntale a alguien mas.

Explanation:

lo siento:(

7 0
3 years ago
Which statement correctly contrasts science and pseudoscience
mojhsa [17]
brainly.com/question/1470976 Hope this helps!
8 0
3 years ago
Read temprature on thermometer i am confusion
balu736 [363]

Answer:

a)22.2°C after adding magnesium

b)17.3°C before adding magnesium

c) 4.9 is change

8 0
3 years ago
The solubility of water in diethyl ether has been reported to be 1.468 % by mass.' Assuming that 23.0 mL of diethyl ether were a
melomori [17]

Explanation:

As it is given that solubility of water in diethyl ether is 1.468 %. This means that in 100 ml saturated solution water present is 1.468 ml.

Hence, amount of diethyl ether present will be calculated as follows.

                          (100ml - 1.468 ml)

                        = 98.532 ml

So, it means that 98.532 ml of diethyl ether can dissolve 1.468 ml of water.

Hence, 23 ml of diethyl ether can dissolve the amount of water will be calculated as follows.

          Amount of water = \frac{1.468 ml \times 23 ml}{98.532 ml}

                                       = 0.3427 ml

Now, when magnesium dissolves in water then the reaction will be as follows.

                Mg + H_{2}O \rightarrow Mg(OH)_{2}

Molar mass of Mg = 24.305 g

Molar mass of H_{2}O = 18 g

Therefore, amount of magnesium present in 0.3427 ml of water is calculated as follows.

           Amount of Mg = \frac{24.305 g \times 0.3427 ml}{18 g}  

                                    = 0.462 g

   

6 0
3 years ago
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