Answer:
62.5 moles of O₂.
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
2C₈H₁₈ + 25O₂ —> 16CO₂ + 18H₂O
From the balanced equation above,
2 moles of C₈H₁₈ reacted with 25 moles of O₂.
Finally, we shall determine the number of mole of O₂ needed to react with 5 moles of C₈H₁₈. This can be obtained as shown below:
From the balanced equation above,
2 moles of C₈H₁₈ reacted with 25 moles of O₂.
Therefore, 5 moles of C₈H₁₈ will react with = (5 × 25) / 2 = 62.5 moles of O₂.
Thus, 62.5 moles of O₂ is needed for the reaction.
Answer:
3
Explanation:
Order of in the mass action law is the coefficient which is raised to the active concentration of the reactants. It is experimentally determined and can be zero, positive negative or fractional.
The order of the whole reaction is the sum of the order of each reactant which is raised to its power in the rate law.
Thus,
For the reaction:-
2Mg+O₂→2MgO
Rate = k[Mg][O₂]²
Order w.r.t. Mg = 1
Order w.r.t. O₂ = 2
<u>So, order of the overall reaction = 1 + 2 = 3</u>
Answer:
helium=1,2atm
argon=2,8atm
Explanation:
partial is pressure exerted by each gas in a system since 30% is helium it means 70% is argon
argon =70%x4
helium=30%4
The answer is A- single bonds made by 1 atom to 3 other atoms within a molecule
Answer:
Explanation:
The nuclear equation from which you have to identify the missing element is:
- ²³⁹₉₄ Pu + ¹₀n → ___ + ¹³⁴₅₄Xe + 3 ¹₀n
The superscripts to the left of each chemical symbol are the mass number of the atoms (number of protons plus neutrons) and the subscripts to the left of the chemical symbols are the atomic numbers of the atoms (number of protons).
Thus, such equation must be read as "an atom of plutonium-239 is bombarded with a neutron and produces one atom of an unkwon element, one atom of xenon-134, and 3 neutrons".
To find the identity of the missing element you must do two balances: mass number and atomic number.
Mass number:
Hence, the mass number of the missing element is 103.
Atomic number:
Hence, the atomic number of the missing element is 40.
In a periodic table you can find that the element with atomic number 40 is zirconium, Zr.
Thus, the identity of the missing isotope is zirconium-103, ¹⁰³₄₀Zr.
And the complete equation is:
- ²³⁹₉₄ Pu + ¹₀n → ¹⁰³₄₀ Zr + ¹³⁴₅₄Xe + 3 ¹₀n
