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valentinak56 [21]
3 years ago
15

In the measurement 5.678 grams, which Is the uncertain digit?​

Chemistry
2 answers:
Ainat [17]3 years ago
5 0

8 is the uncertain digit.

NeTakaya3 years ago
4 0

Answer:

  • <u>The last digit, 8, is the uncertain one.</u>

Explanation:

Every measurement has an uncertainty associated with the instrument used to measure.

The measurement represented by 5.678 grams has 4 significant digits: all the non-zero digits in a measurement are significant (non-zero digits and zeros between non-zero digits are always significant).

When you use a scale to measure the mass of an object, such scale has an appreciation and the last number that you can read is between two possible numbers, i.e. the digit 8 in the given measurement could have been a little bigger or a little smaller, so the real measurement could have been something between 5.677 . . . or 5.678 . . .

The last digit in any measurement is always uncertain.

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garri49 [273]
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6 0
3 years ago
Be sure to answer all parts. Consider the reaction A + B → Products From the following data obtained at a certain temperature, d
worty [1.4K]

Answer : The order of reaction with respect to A is, first order reaction.

The order of reaction with respect to B is, zero order reaction.

The overall order of reaction is, first order reaction.  

Explanation :

Rate law is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

For the given chemical equation:

A+B\rightarrow Products

Rate law expression for the reaction:

\text{Rate}=k[A]^a[B]^b

where,

a = order with respect to A

b = order with respect to B

Expression for rate law for first observation:

3.20\times 10^{-1}=k(1.50)^a(1.50)^b ....(1)

Expression for rate law for second observation:

3.20\times 10^{-1}=k(1.50)^a(2.50)^b ....(2)

Expression for rate law for third observation:

6.40\times 10^{-1}=k(3.00)^a(1.50)^b ....(3)

Dividing 1 from 2, we get:

\frac{3.20\times 10^{-1}}{3.20\times 10^{-1}}=\frac{k(1.50)^a(2.50)^b}{k(1.50)^a(1.50)^b}\\\\1=1.66^b\\b=0

Dividing 1 from 3, we get:

\frac{6.40\times 10^{-1}}{3.20\times 10^{-1}}=\frac{k(3.00)^a(1.50)^b}{k(1.50)^a(1.50)^b}\\\\2=2^a\\a=1

Thus, the rate law becomes:

\text{Rate}=k[A]^1[B]^0

\text{Rate}=k[A]

Thus,

The order of reaction with respect to A is, first order reaction.

The order of reaction with respect to B is, zero order reaction.

The overall order of reaction is, first order reaction.

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3 0
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Where are metals, nonmetals, metalloids, and the noble gases located on the periodic table?
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Answer:

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