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MrRissso [65]
3 years ago
6

A ray of light that strikes a surface is known as?

Physics
2 answers:
Lena [83]3 years ago
7 0

A ray of light that strikes a surface is known as the <em>incident ray.  (d)</em>

lisov135 [29]3 years ago
6 0

In the physics of optics, it has been defined that the incident rays are the rays which strikes the surface.

Answer : Option D

<u>Explanation:</u>

When the ray of light strikes the surface it is know as ''incident ray''. The angle which it makes with the normal or the perpendicular imagined or drawn to the surface is the ''incident angle''.

According to the ''Law of Reflection'', the incident ray after striking the surface is reflected back, the ray which leaves the surface is called the ''Reflected Ray''. The angle which is made between the same normal and reflected ray is the reflected angle.

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A train traveled 100 kilometers north in 2 hours. After exchanging some railroad cars, it traveled 100 kilometers south in 2 hou
hodyreva [135]

Answer:Due to change in direction

Explanation:

Given

Initially train has traveled a 100 km in North and after exchanging some railroad cars, it traveled 100 in south.

The velocity of the train changes as it direction of motion changes. Velocity is the vector quantity which require direction and magnitude for its reperesentation.

7 0
2 years ago
A circular coil 14.0 cm in diameter and containing nine loops lies flat on the ground. The Earth's magnetic field at this locati
sp2606 [1]

Answer:

a)T = 2.9*10^{-5} N-m

b) north edge will rise up

Explanation:

torque on the coil is given as

T = NIABsin\theta

where N is number of loop =  9 loops

i is current = 7.80 A

-B -earth magnetic field = 5.00*10^{-5} T

A- area of circular coil

A = \frac{\pi d^{2}}{4}

A =\frac{\pi .14^{2}}{4}

A =0.015 m2

PUTITNG ALL VALUE TO GET TORQUE

T = 9*7.8*0.015*5*10^{-5} sin{90-56}

T = 2.9*10^{-5} N-m

b) north edge will rise up

3 0
3 years ago
Read 2 more answers
Why does every element except hydrogen need at least one neutron and its nucleus?
scoray [572]

Answer:

It needs attractive force from the strong nuclear interaction to counter the electrostatic repulsion between the protons.

Explanation:

It has to counter

8 0
3 years ago
you run 2.5m/s horizontally from the edge of a cliff and 3 sec . later hit the ground, how high is the cliff?
bonufazy [111]
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3 years ago
If the 3rd harmonic has a frequency of 600Hz, the frequency of the fundamental is ____________?
castortr0y [4]

Answer:

Fundamental frequency is 200 Hz.

Explanation:

It is given that,

Frequency of the 3rd harmonic is 600 Hz.

Let f is the fundamental frequency. We need to find the value of f. The frequency of third harmonic is given by :

3f=600\ Hz

So, fundamental frequency f is equal to :

f = 200 Hz

So, the fundamental frequency of the harmonics is 200 Hz. Hence, this is the required solution.

4 0
3 years ago
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