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MrRissso [65]
3 years ago
6

A ray of light that strikes a surface is known as?

Physics
2 answers:
Lena [83]3 years ago
7 0

A ray of light that strikes a surface is known as the <em>incident ray.  (d)</em>

lisov135 [29]3 years ago
6 0

In the physics of optics, it has been defined that the incident rays are the rays which strikes the surface.

Answer : Option D

<u>Explanation:</u>

When the ray of light strikes the surface it is know as ''incident ray''. The angle which it makes with the normal or the perpendicular imagined or drawn to the surface is the ''incident angle''.

According to the ''Law of Reflection'', the incident ray after striking the surface is reflected back, the ray which leaves the surface is called the ''Reflected Ray''. The angle which is made between the same normal and reflected ray is the reflected angle.

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You notice that the price of Blu-ray players falls and the quantity of Blu-ray players sold increases. This set of observations
satela [25.4K]

Answer:

Option C

Explanation:

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Thus When supply curve is shifted to the right the demand curve is moved down accordingly.

6 0
3 years ago
Laney et al. (false memory):(a) Outline the rating scale used in the Food History Inventory [2 marks]
djverab [1.8K]

Answer: The rating scale that is used in food history inventory is from 1 to 8.

Explanation:

In this case the participants have to rate 24 items on a scale of 1 to 8.There are variety of questions related to food or fooding habits.

The questions like do you go out for food?

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The questions like this has to be answered in a way . It is done in order to see the preferences and false memory  regarding the food preference that people have.

6 0
3 years ago
Conditional probability involves events that are independent. true or false?
kiruha [24]
Its false I got It right .


3 0
3 years ago
Please help! Will give brainliest. 10 points. Show work!
Natasha_Volkova [10]

Answer:

421.83 m.

Explanation:

The following data were obtained from the question:

Height (h) = 396.9 m

Initial velocity (u) = 46.87 m/s

Horizontal distance (s) =...?

First, we shall determine the time taken for the ball to get to the ground.

This can be calculated by doing the following:

t = √(2h/g)

Acceleration due to gravity (g) = 9.8 m/s²

Height (h) = 396.9 m

Time (t) =.?

t = √(2h/g)

t = √(2 x 396.9 / 9.8)

t = √81

t = 9 secs.

Therefore, it took 9 secs fir the ball to get to the ground.

Finally, we shall determine the horizontal distance travelled by the ball as illustrated below:

Time (t) = 9 secs.

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s = ut

s = 46.87 x 9

s = 421.83 m

Therefore, the horizontal distance travelled by the ball is 421.83 m

5 0
3 years ago
The near point of a farsighted person's uncorrected eyes is 80 cm. what power contact lens should be used to move the near point
makvit [3.9K]
To solve this problem, we will get f and then we will use it to calculate the power.

So, for this farsighted person,
do = 25 cm and di = -80
Therefore:
1/f = (1/25) + (1/-80) = 0.00275 = 0.275 m

Power = 1/f = 1/0.275 = +3.6363 Diopeters.
This means that the lens is converging.
5 0
3 years ago
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