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3 years ago

A ray of light that strikes a surface is known as?

Physics

2 answers:

Lena [83]3 years ago

7 0

A ray of light that strikes a surface is known as the <em>incident ray. (d)</em>

lisov135 [29]3 years ago

6 0

In the physics of optics, it has been defined that the incident rays are the rays which strikes the surface.

Answer : Option D

<u>Explanation:</u>

When the ray of light strikes the surface it is know as ''incident ray''. The angle which it makes with the normal or the perpendicular imagined or drawn to the surface is the ''incident angle''.

According to the ''Law of Reflection'', the incident ray after striking the surface is reflected back, the ray which leaves the surface is called the ''Reflected Ray''. The angle which is made between the same normal and reflected ray is the reflected angle.

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What force is necessary to accelerate a 2500 kg care from rest to 20 m/s over 10 seconds?

EleoNora [17]

Force = mass x acceleration
force = 2500kg x (20m/s / 10m/s)
force = 2500kg x 2m/s^2
force = 5000kg m/s^2 = 5kN

i hope this is right (^^)

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2 years ago

Two common terms for a decrease in velocity are

Colt1911 [192]

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3 years ago

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Cuanto cambia la entropía de 0.50 kg de vapor de mercurio [Lv: 2.7 x 10⁵ j/kg ] al calentarse en su punto de ebullición de 357°

lord [1]

Answer:

La entropía del vapor de mercurio cambia en 214.235 joules por Kelvin.

Explanation:

Por definición de entropía ( $S$ ), medida en joules por Kelvin, tenemos la siguiente expresión:

$dS = \frac{\delta Q}{T}$ (1)

Donde:

$Q$ - Ganancia de calor, en joules.

$T$ - Temperatura del sistema, en Kelvin.

Ampliamos (1) por la definición de calor latente:

$dS = \frac{L_{v}}{T}\cdot dm$ (1b)

Donde:

$m$ - Masa del sistema, en kilogramos.

$L_{v}$ - Calor latente de vaporización, en joules

Puesto que no existe cambio en la temperatura durante el proceso de vaporización, transformamos la expresión diferencial en expresión de diferencia, es decir:

$\Delta S = \frac{\Delta m \cdot L_{v}}{T}$

Como vemos, el cambio de la entropía asociada al cambio de fase del mercurio es directamente proporcional a la masa del sistema. Si tenemos que $m = 0.50\,kg$ , $L_{v} = 2.7\times 10^{5}\,\frac{J}{kg}$ and $T = 630.15\,K$ , entonces el cambio de entropía es:

$\Delta S = \frac{(0.50\,kg)\cdot \left(2.7\times 10^{5}\,\frac{J}{kg} \right)}{630.15\,K}$

$\Delta S = 214.235 \,\frac{J}{K}$

La entropía del vapor de mercurio cambia en 214.235 joules por Kelvin.

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3 years ago

Zoe finds that the temperature of a substance is 12 degrees Celsius. What does this tell Zoe about the substance?

maks197457 [2]

Given the temperature, we can tell if the substance is cold or not relative to the reference temperature. For example, compared to the substance having a temperature of 15 degrees C, the substance is colder and it is hotter from the substance of temperature lesser than 12 degrees C.

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2 years ago

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An oil gusher shoots crude oil 25.0 m into the air through a pipe with a 0.100-m diameter. Neglecting air resistance but not the

Mariana [72]

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v=\sqrt{2gh}[/tex]

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