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allochka39001 [22]
3 years ago
10

An engine does 10 J of work and exhausts 25 J of waste heat during each cycle.

Physics
1 answer:
noname [10]3 years ago
4 0
The thermal efficiency is defined as follows

\eta = 1 - \frac{Q_{\text{out}}}{Q_\text{in}},

and the energy which is put into the system is

Q_{\text{in}} = W_\text{out} + Q_\text{out}.

In your case Q_\text{in} = 25 \text{ J},W_\text{out}=10 \text{ J}.

So Q_\text{out}=10 \text{ J} which gives an efficiency of

\eta = 1 - \frac{10 \text{ J}}{25 \text { J}} = 0.6 = 60 \%.





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