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Luda [366]
3 years ago
9

Andrew has a four-year college loan for $20,000. The lender charges a simple interest rate of 5 percent. How much interest will

he have to pay? simple interest = P × r × t A. $800 B. $4,000 C. $10,000
Physics
1 answer:
atroni [7]3 years ago
7 0

Answer:

B. $4,000

Explanation:

The formula for the simple interest is

interest = P\cdot r \cdot t

where

P is the principal

r is the interest rate

t is the number of years

In this problem,

P = 20,000 $

r = 0.05

t = 4 years

So the interest is

P=(20,000 $)(0.05 )(4)=4,000 $

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Andreyy89
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4 0
3 years ago
If two children, with masses of 16 kg and 24 kg , sit in seats opposite one another, what is the moment of inertia about the rot
Elena-2011 [213]

Answer:

The moment of inertia about the rotation axis is 117.45 kg-m²

Explanation:

Given that,

Mass of one child = 16 kg

Mass of second child = 24 kg

Suppose a playground toy has two seats, each 6.1 kg, attached to very light rods of length r = 1.5 m.

We need to calculate the moment of inertia

Using formula of moment of inertia

I=I_{1}+I_{2}

I=(m+m_{1})\times r^2+(m+m_{2})\times r^2

m = mass of seat

m₁ =mass of one child

m₂ = mass of second child

r = radius of rod

Put the value into the formula

I=(16+6.1)\times(1.5)^2+(24+6.1)\times(1.5)^2

I=117.45\ kg-m^2

Hence, The moment of inertia about the rotation axis is 117.45 kg-m²

8 0
3 years ago
A ball is fired at an angle of 45 degrees, the angle that yields the maximum range in the absence of air resistance. What is the
Nesterboy [21]
Look at the picture for the answer

7 0
3 years ago
Read 2 more answers
A particle with a mass of 6.64 × 10–27 kg and a charge of +3.20 × 10–19 C is accelerated from rest through a potential differenc
blondinia [14]

Answer:

Explanation:

Given that,

Mass m = 6.64×10^-27kg

Charge q = 3.2×10^-19C

Potential difference V =2.45×10^6V

Magnetic field B =1.6T

The force in a magnetic field is given as Force = q•(V×B)

Since V and B are perpendicular i.e 90°

Force =q•V•BSin90

F=q•V•B

So we need to find the velocity

Then, K•E is equal to work done by charge I.e K•E=U

K•E =½mV²

K•E =½ ×6.64×10^-27 V²

K•E = 3.32×10^-27 V²

U = q•V

U = 3.2×10^-19 × 2.45×10^6

U =7.84×10^-13

Then, K•E = U

3.32×10^-27V² = 7.84×10^-13

V² = 7.84×10^-13 / 3.32×10^-27

V² = 2.36×10^14

V=√2.36×10^14

V = 1.537×10^7 m/s

So, applying this to force in magnetic field

F=q•V•B

F= 3.2×10^-19 × 1.537×10^7 ×1.6

F = 7.87×10^-12 N

6 0
3 years ago
Read 2 more answers
A man of mass 50kg ascends a flight of stairs 5m high in 5 seconds. If acceleration due to gravity is 10ms-2, the power expended
Setler79 [48]

The power expended is 500 W

Explanation:

First of all, we start by calculating the work done by the man in order to ascend: this is equal to the gravitational potential energy gained by the man, which is

W=mg\Delta h

where

m = 50 kg is the mass of the man

g=10 m/s^2 is the acceleration of gravity

\Delta h = 5 m is the change in height

Substituting,

W=(50)(10)(5)=2500 J

Now we can calculate the power expended, which is given by

P=\frac{W}{t}

where

W = 2500 J is the work done

t = 5 s is the time elapsed

Substituting, we find

P=\frac{2500}{5}=500 W

Learn more about power:

brainly.com/question/7956557

#LearnwithBrainly

7 0
3 years ago
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