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Vikentia [17]
4 years ago
9

A 0.15 m aqueous solution of a weak acid has a freezing point of -0.31 °C. What is the percent ionization of this weak acid at t

his concentration? The molal freezing-point-depression constant of water is 1.86 °C/m.
Chemistry
1 answer:
tensa zangetsu [6.8K]4 years ago
4 0

Answer:

11%

Explanation:

1) Calculate van 't Hoff factor:

Δt = i Kf m

0.31 = i (1.86) (0.15)

i = 1.111

2) Calculate value for [H+]:

CCl3COOH ⇌ H+ + CCl3COO¯

total concentration of all ions in solution equals:

(1.11) (0.15) = 0.1665 m

This is a molality, but we will act as if it a molarity since we will assume the density of the solution is 1.00 g/cm3, which makes the molarity equal to the molality.

0.1665 = (0.15 − x) + x + x

x = 0.0165 M

3) Calculate the percent dissociation:

0.0165/ 0.15 = 11 %

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The pressure inside the container would increase with each additional pump.

Explanation:

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How can I differentiate between Ionic compounds, molecular compounds, and acids given only the formula? I need to be able to fin
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If I need 2.2 moles of CO2 , and I have excess Fe2O3 , how many moles of C do I need?
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Explanation:

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It is clear that 1.0 moles of Fe₂O₃  react with 1.0 mole of C to produce 1.0 mole of Fe and 3.0 moles of CO₂.

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Change for a liquid state to a solid state is known as what phase change?
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