The coefficient of friction is 0.39
Explanation:
The equation of the forces along the direction parallel to the incline is the following:
(1)
where
is the component of the weight parallel to the incline (acting downward), with
m = 50 kg being the mass of the couch
(acceleration of gravity)
is the angle of the ramp
is the force of friction, acting up along the plane, with
being the coefficient of friction
N is the normal force
is the acceleration
The equation of the forces along the direction perpendicular to the plane is
(2)
where is the component of the weight perpendicular to the plane
From (2) we find
And substituting into (1)
And solving for , we find
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Answer:
Keep on moving
Explanation:
Newton's first law states "that, if a body is at rest or moving at a constant speed in a straight line, it will remain at rest or keep moving in a straight line at constant speed unless it is acted upon by a force."
Answer:
m=0.5kg
h = 180 cm =1.8 mh=180cm=1.8m
Initial potential energy of the object is:
E_p=m*g*hE
p
=m∗g∗h
Kinetic energy at the surface:
E_k=\frac{mv^2}{2}E
k
=
2
mv
2
According to the law of conservation of energy (assuming no air resistance):
E_p = E_kE
p
=E
k
mgh=\frac{mv^2}{2}mgh=
2
mv
2
Solving for v:
v=\sqrt{2gh}v=
2gh
p=mvp=mv
So,
p= m*v = m\sqrt{2gh}p=m∗v=m
2gh
Calculating:
p= 0.5\sqrt{2*9.8*1.8}\approx 2.97 \frac{kg*m}{s}p=0.5
2∗9.8∗1.8
≈2.97
s
kg∗m
Answer:
p \approx 2.97 \frac{kg*m}{s}p≈2.97
s
kg∗m
You have done 43.9 joules of work to lift the can.
1) 30 volts is correct
2) Rt = (4x6)/(4+6)=2.4 Ω
3) P = I^2 x R = 36 W
we use AC because it's easy to transmit via 3 phase on cables and easy to step up and down