Answer:
Q = 19255.6 j
Explanation:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
Given data:
Mass of water = 46 g
change in temperature = ΔT = 100-0.0 = 100 °C
Heat absorbed by water = ?
Solution:
Specific heat capacity of water = 4.186 j/g. °C
Q = m.c. ΔT
Q = 46 g×4.186 j/g. °C×100 °C
Q = 19255.6 j
It would be Water and salts
Answer:
V= 37.0 mL
Explanation:
First find the moles of the known substance (CuCl2)
n= cv
where
n is moles
c is concentration
v is volume ( in litres)
n= 0.108 × 0.0946
n=0.0102168
Using the mole ratio in the balanced reaction, we can find the moles of Na3PO4
n (Na3PO4)= n (CuCl2) × 2/3
=0.0102168 × 2/3
=0.0068112
Now we have all the necessary values to calculate the volume
v=n/c
v= 0.0068112/0.184
v= 0.0370173913 L
v= 37.0 mL
Answer:
the answer is Sodium (Na)