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Bezzdna [24]
3 years ago
12

What is the rate law for step 1 of this reaction? express your answer in standard masteringchemistry notation. for example, if t

he rate law is k[a][c]3 type k*[a]*[c]^3?
Chemistry
2 answers:
eimsori [14]3 years ago
7 0
Hehshdhjd shshhsjawkkskssss
Tems11 [23]3 years ago
5 0

Answer:

rate = k*[A]^3

Explanation:

The following information is missing in the question:

<em>Consider the following elementary steps that make up the mechanism of a certain reaction</em>

<em>1. 3A -> B+C </em>

<em>2. B+2D -> C+F</em>

In elementary reactions, the order of each reactant in the rate law is equal to the coefficient in the balanced equation. Therefore, for the first step:

rate = k*[A]^3

You might be interested in
How many moles are in 3.27 x 1027 atoms of carbon (C)? ​
rusak2 [61]

Answer:

Try:

1. How many atoms are in 6.5 moles of zinc?

6.5 moles 6.02 x 1023 atoms = 3.9 x 1024 atoms

1 mole

2. How many moles of argon are in a sample containing 2.4 x 1024 atoms of argon?

2.4 x 1024 atoms of argon 1 mole = 4.0 mol

6.02 x 1023 atoms

3. How many moles are in 2.5g of lithium?

2.5 grams Li 1 mole = 0.36 mol

6.9 g

4. Find the mass of 4.8moles of iron.

4.8 moles 55.8 g = 267.84 g = 270g

1 mole

Explanation:

i think i did it about right..?? :-(

5 0
3 years ago
a mechanical pencil has the mass of 55.5 grams the volume of the pencil is 11.5 cubic centimeter what is the density of the penc
Andrei [34K]

Answer:

D = M/V

Explanation:

D = 55.5g/11.5cm^3

D = 4.83g/cm^3

3 0
3 years ago
Vitamin K is involved in normal blood clotting. When 0.802 g of vitamin K is dissolved in 25.0 g of camphor, the freezing point
xenn [34]

Answer:

Molar mass of vitamin K = 450.56\frac{g}{mol}[/tex]

Explanation:

The freezing point of camphor = 178.4 ⁰C

the Kf of camphor =  37.7°C/m

where : m = molality

the relation between freezing point depression and molality is

Depression in freezing point = Kf X molality

Where

Kf = cryoscopic constant of camphor

molality = moles of solute dissolved per kg of solvent.

putting values

2.69°C = 37.7°C/m X molality

molality = 0.0714 mol /kg

molality=\frac{molesofvitaminK}{massofcamphor(kg)}=\frac{moles}{0.025}

moles of vitamin K = 0.0714X0.025 = 0.00178 mol

we know that moles are related to mass and molar mass of a substance as:

moles=\frac{mass}{molarmass}

For vitamin K the mass is given = 0.802 grams

therefore molar mass = \frac{mass}{moles}=\frac{0.802}{0.00178}=450.56\frac{g}{mol}

7 0
3 years ago
The author of Space Systems: All About Eclipses makes the point that seeing a total solar eclipse is rare. How does the author u
Ilia_Sergeevich [38]

Answer:

<h3>A.</h3>

Explanation:

If A does not work, please use the alteritive choice, which is D!

が機能しない場合は、別の選択肢であるDを使用してください。 ^ 3 ^

3 0
3 years ago
What is the theoretical yield of Li3N in grams when 12.8 g of Li is heated with 34.9 g of N2?
Olenka [21]

Answer:- 21.4 grams of Li_3N are formed.

Solution:- The balanced equation is:

6Li+N_2\rightarrow 2Li_3N

From this equation, lithium and nitrogen reacts in 6:1 mol ratio. Limiting reactant gives the theoretical yield of the product. We will calculate the grams of the product for the given grams of both the reactants and see which one of them gives the limited amount of the product. This limited amount of the product will be the theoretical yield.

The molar mass of Li is 6.94 gram per mol and for N_2 It is 28.02 gram per mol. The molar mass of Li_3N is 34.83 gram per mol. The calculations for the grams of the product for given grams of both the reactants are shown below:

12.8gLi(\frac{1molLi}{6.94gLi})(\frac{2molLi_3N}{6molLi})(\frac{34.83gLi_3N}{1molLi_3N})

= 21.4gLi_3N

34.9gN_2(\frac{1molN_2}{28.02gN_2})(\frac{2molLi_3N}{1molN_2})(\frac{34.83gLi_3N}{1molLi_3N})

= 86.8gLi_3N

From above calculations, Li gives least amount of the product. So, 21.4 g of Li_3N are formed.

4 0
3 years ago
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