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kodGreya [7K]
3 years ago
13

A flashlight has a filament with a resistance of 9.8 Ohms. If the batteries provide 3.0 V, what is the current through the filam

ent?
Physics
1 answer:
Evgen [1.6K]3 years ago
7 0

Current = (voltage) / (resistance)

Current= (3.0volts) / (9.8 ohms)  =<em>  0.306 ampere</em> = 306 milliamperes (mA)

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It says energy can't be created or destroyed

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Which of the following statements is true?
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All the radiation from stars is the result of nuclear fusion in their cores.

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Select the correct answer.
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A merry-go-round with a rotational inertia of 600 kg m2 and a radius of 3. 0 m is initially at rest. A 20 kg boy approaches the
Margaret [11]

Hi there!

\boxed{\omega = 0.38 rad/sec}

We can use the conservation of angular momentum to solve.

\large\boxed{L_i = L_f}

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L = I\omega

We can begin by writing out the scenario as a conservation of angular momentum:

I_m\omega_m + I_b\omega_b = \omega_f(I_m + I_b)

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\omega_m = angular velocity of merry go round (rad/sec)

\omega_f = final angular velocity of COMBINED objects (rad/sec)

I_b = moment of inertia of boy (kgm²)

\omega_b= angular velocity of the boy (rad/sec)

The only value not explicitly given is the moment of inertia of the boy.

Since he stands along the edge of the merry go round:

I = MR^2

We are given that he jumps on the merry-go-round at a speed of 5 m/s. Use the following relation:

\omega = \frac{v}{r}

L_b = MR^2(\frac{v}{R}) = MRv

Plug in the given values:

L_b = (20)(3)(5) = 300 kgm^2/s

Now, we must solve for the boy's moment of inertia:

I = MR^2\\I = 20(3^2) = 180 kgm^2

Use the above equation for conservation of momentum:

600(0) + 300 = \omega_f(180 + 600)\\\\300 = 780\omega_f\\\\\omega = \boxed{0.38 rad/sec}

8 0
2 years ago
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Leno4ka [110]

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So, the magnification is

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7 0
3 years ago
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