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3 years ago

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A flashlight has a filament with a resistance of 9.8 Ohms. If the batteries provide 3.0 V, what is the current through the filam

ent?

1 answer:

Evgen [1.6K]3 years ago

7 0

Current = (voltage) / (resistance)

Current= (3.0volts) / (9.8 ohms) =<em> 0.306 ampere</em> = 306 milliamperes (mA)

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