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blsea [12.9K]
3 years ago
15

How would convection warm up an iguana cage

Physics
1 answer:
harina [27]3 years ago
3 0
Using a basking spot so some sort of heated object, for example heating lamp or heating pad.
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Millikan is doing his oil drop experiment. He has a droplet with radius 1.6 µm suspended motionless in a uniform electric field
swat32

Answer:

The charge on the droplet is 3.106\times10^{-16}\ C.

Yes, quantization of charge is obeyed within experimental error.

Explanation:

Given that,

Radius = 1.6μm

Electric field = 46 N/C

Density of oil = 0.085 g/cm³

We need to calculate the charge on the droplet

Using formula of force

F= qE

mg=qE

V\times\rho\times g=qE

q=\dfrac{V\times\rho}{E}

q=\dfrac{\dfrac{4}{3}\pi\times r^3\times\rho\times g}{E}

Put the value into the formula

q=\dfrac{\dfrac{4}{3}\times\pi\times(1.6\times10^{-6})^3\times85\times9.8}{46}

q=3.106\times10^{-16}\ C

We need to calculate the quantization of charge

Using formula of quantization

n = \dfrac{q}{e}

Put the value into the formula

n=\dfrac{3.106\times10^{-16}}{1.6\times10^{-19}}

n=1941.25

Yes, quantization of charge is obeyed within experimental error.

Hence, The charge on the droplet is 3.106\times10^{-16}\ C.

Yes, quantization of charge is obeyed within experimental error.

7 0
3 years ago
Read 2 more answers
What energy transformations take place in Joule's system?
attashe74 [19]

The gravitational potential energy of the weight changes to motion energy when the weight moves down and the paddle wheel spins. The motion energy changes to thermal energy, causing the water’s temperature to rise.

(fast explanation for my fellow edmentum kids :))

6 0
4 years ago
Read 2 more answers
Please help me on my physics hw ​
MatroZZZ [7]

Answer:

1. 11 A

2. 240 V

3. 8 Ω

4. 60 C

5. 14400 C

Explanation:

1. Determination of the current.

Voltage (V) = 110 V

Resistance (R) = 10 Ω

Current (I) =?

V = IR

110 = I × 10

Divide both side by 10

I = 110 / 10

I = 11 A

2. Determination of the voltage

Current (I) = 3 A

Resistance (R) = 80 Ω

Voltage (V) =?

V = IR

V = 3 × 80

V = 240 V

3. Determination of the resistance.

Current (I) = 0.5 A

Voltage (V) = 4 V

Resistance (R) =?

V = IR

4 = 0.5 × R

Divide both side by 0.5

R = 4 / 0.5

R = 8 Ω

4. Determination of the charge

Current (I) = 2 A

Time (t) = 30 s

Charge (Q) =?

Q = it

Q = 2 × 30

Q = 60 C

5. Determination of the charge.

We'll begin by converting 20 mins to seconds. This can be obtained as follow:

1 min = 60 s

Therefore,

20 mins = 20 × 60

20 mins = 1200 s

Finally, we shall determine the charge as follow:

Current (I) = 12 A

Time (t) = 1200 s

Charge (Q) =?

Q = it

Q = 12 × 1200

Q = 14400 C

6 0
3 years ago
Which is not an example of work being done?
mezya [45]
C. Carrying a backpack to class
7 0
3 years ago
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The magnitude of the electric current is directly proportional to the _____________ of the electric field.
Harlamova29_29 [7]
The magnitude of the electric current is directly proportional to the "Electric Charge" <span>of the electric field.

Hope this helps!</span>
7 0
3 years ago
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