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blsea [12.9K]
3 years ago
15

How would convection warm up an iguana cage

Physics
1 answer:
harina [27]3 years ago
3 0
Using a basking spot so some sort of heated object, for example heating lamp or heating pad.
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Conclusion on ohm's law experiment ​
Free_Kalibri [48]

Answer:

Explanation:

In our previous articles, we observed the theoretical formulas of Ohm’s law, its calculations in the lab report, and experiment. Today you’ll learn the verification of theory vs experimental results on a 1 kΩ resistor.

The theoretical results are obtained from the formula of Ohm’s law: V = IR. The experimental verification is provided for a metal film 1 kΩ (±0.05%). We have used a high-quality resistor with negligible tolerance value so as to reduce the tolerance error.

The little problem in our calculations arises due to improper handling of multimeter probes. You can learn the complete method to perform the Ohm’s experiment here and can calculate the current values by using the Ohm’s law calculator.

6 0
3 years ago
If you walk eight blocks north and then three blocks south from your home what is your position compared to your home? what dist
Solnce55 [7]
Imagine you walk 8 blocks, then you turn back and walk 3 blocks
your position from your home is 8 - 3 = 5

your distance is 8 +  3 = 11
6 0
3 years ago
Which is heavier a pound of bricks or a pound of feather
Shkiper50 [21]

Answer:

pound of bricks

meh wrong ? XD

4 0
2 years ago
Read 2 more answers
A 2.00 kg block hangs from a spring balance calibrated in Newtons that is attached to the ceiling of an elevator.(a) What does t
tresset_1 [31]

Answer:

Part a)

Reading = 2.00 kg

Part b)

Reading = 2.00 kg

Part c)

Reading = 4.04 kg

Part d)

from t = 0 to t = 4.9 s

so the reading of the scale will be same as that of weight of the block

Then its speed will reduce to zero in next 3.2 s

from t = 4.9 to t = 8.1 s

The reading of the scale will be less than the actual mass

Explanation:

Part a)

When elevator is ascending with constant speed then we will have

F_{net} = 0

T - mg = 0

T = mg

So it will read same as that of the mass

Reading = 2.00 kg

Part b)

When elevator is decending with constant speed then we will have

F_{net} = 0

T - mg = 0

T = mg

So it will read same as that of the mass

Reading = 2.00 kg

Part c)

When elevator is ascending with constant speed 39 m/s and acceleration 10 m/s/s then we will have

F_{net} = ma

T - mg = ma

T = mg + ma

Reading is given as

Reading = \frac{mg + ma}{g}

Reading = 2.00\frac{9.81 + 10}{9.81}

Reading = 4.04 kg

Part d)

Here the speed of the elevator is constant initially

from t = 0 to t = 4.9 s

so the reading of the scale will be same as that of weight of the block

Then its speed will reduce to zero in next 3.2 s

from t = 4.9 to t = 8.1 s

The reading of the scale will be less than the actual mass

3 0
3 years ago
What si unit measures speed ?
dlinn [17]
Hmm doesnt soujd familiar
4 0
3 years ago
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