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Kaylis [27]
3 years ago
8

Calculate the acid dissociation constant of a weak monoprotic acid if a 0.5M solution of this acid gives a hydrogen-ion concentr

ation of 0.000 1M? Show your work.
Hint: Monoprotic means containing one proton.

Please help thanks a lot!
Chemistry
1 answer:
RUDIKE [14]3 years ago
4 0
Let the acid be HA.
The chemical formula for this acid will be the following:

HA \rightleftharpoons  H^{+}+A^{-}

The formula for the <span>acid dissociation constant will be the following:

</span>K_a= \dfrac{[H^+][A^-]}{[HA]}
<span>
We know [H+]=0.0001 (it's given).
However, we must find [A-] and [HA] in order to solve for the constant.

We find that [A-]=[H+] by using a electroneutrality equation.
Also, we can create a concentration equation to find [HA].

</span>0.5M=[A^-]+[HA]
[HA]=0.5M-[A^-]
<span>
Now, we can find the acid dissociation constant.

</span>K_a= \dfrac{[H^+][A^-]}{0.5M-[A^-]}

= \dfrac{0.0001*0.0001}{0.5-0.0001} = 2.0*10^{-8}
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