The current is defined as the ratio between the charge Q flowing through a certain point of a wire and the time interval,

:

First we need to find the net charge flowing at a certain point of the wire in one second,

. Using I=0.92 A and re-arranging the previous equation, we find

Now we know that each electron carries a charge of

, so if we divide the charge Q flowing in the wire by the charge of one electron, we find the number of electron flowing in one second:
1.) The object's Velocity
Faster it goes, more kinetic energy it has
Answer:
x=22.57 m
Explanation:
Given that
35 m in W of S
angle = 40 degrees
25 m in east
From the diagram
The angle

From the triangle OAB


x=22.57 m
Therefore the answer of the above problem will be 22.57 m
They enable us to dig deeper into the electron configurations by making us focus on electrons' quantum nature