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3 years ago

15

A mobile phone is pulled northward by a force of 10 n and at the same time pulled southward by another force of 15 n. the result

ant force on the phone is

1 answer:

makvit [3.9K]3 years ago

6 0

5 Southward would be the correct answer.

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A 1.70 kg block slides on a horizontal, frictionless surface until it encounters a spring with a force constant of 955 N/m. The

Mariana [72]

Answer:

The initial speed of the block is 1.09 m/s

Explanation:

Given;

mass of block, m = 1.7 kg

force constant of the spring, k = 955 N/m

compression of the spring, x = 4.6 cm = 0.046 m

From principle of conservation of energy

kinetic energy of the block = elastic potential energy of the spring

¹/₂mv² = ¹/₂kx²

mv² = kx²

$v = \sqrt{\frac{kx^2}{m} }$

where;

v is the initial speed of the block

x is the compression of the spring

$v = \sqrt{\frac{955*(0.046)^2}{1.7} } \\\\v = 1.09 \ m/s$

Therefore, the initial speed of the block is 1.09 m/s

4 0

3 years ago

What is the sound intensity level in decibels? Use the usual reference level of I0 = 1.0×10−12 W/m2.

jek_recluse [69]

Answer:

L = 130 decibels

Explanation:

The computation of the sound intensity level in decibels is shown below:

According to the question, data provided is as follows

I = sound intensity = 10 W/m^2

I0 = reference level = $1 \times 10-12 W/m^2$

Now

Intensity level ( or Loudness)is

$L = log10 \frac{I}{10}$

$L = log10 \frac{10}{1\times 10^{-12}}$

$L = log10 \times 1013$

$= 13 \times 1 ( log10(10) = 1)$

Therefore

L = 13 bel

And as we know that

1 bel = 10 decibels

So,

The Sound intensity level is

L = 130 decibels

5 0

3 years ago

The heater element of a 120 V toaster is a 5.4 m length of nichrome wire, whose diameter is 0.48 mm. The resistivity of nichrome

Ksenya-84 [330]

Answer:

The power drawn by the toaster is closest to:

(A) 370 W

Explanation:

First we calculate the resistance of the nichrome wire (R).

$R=\frac{pL}{A} =\frac{pL}{\pi r^{2} } \\$

Where radious (r), resistance coefficient (p), and Length (L)

$r=\frac{0.48}{2} 10^{-3} m\\\\L=5.4 m\\p=1.3*10^{-3}\varOmega \\\\\\Replacing:\\\\R=\frac{1.3(10)^{-6} *5.4}{\pi* 0.24^{2} (10)^{-6}} =38.7940$

After replace the value in the ohm law power formula to obtain the power consumed:

$P=\frac{V^2}{R} =\frac{120^2}{38.7940} =371.191 Watts$

7 0

2 years ago

Two pebbles, Pebble A and Pebble B, are thrown horizontally with the same force. Pebble A's mass is 3 times the

Hitman42 [59]

Answer:

Pebble A has 1/3 the acceleration as pebble B.

Explanation:

F = m×a

mass of a = 3 × mass of b (m_a = 3 × m_b)

Same starting force, F

m_a = mass of a

m_b = mass of b

a_a = acceleration of a

a_b = acceleration of b

F = m_a × a_a = m_b × a_b

3 × m_b × a_a = m_b × a_b

3 × a_a = a_b

OR

a_a = a_b / 3

5 0

2 years ago

10 PTS. If an electromagnetic wave has a frequency of 8 ⋅ 10^14 H z , what is its wavelength? Use λ=V/F. The speed of light is 3

ad-work [718]

Answer :

The wavelength would be 410 m/s

3 0

2 years ago