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3 years ago

14

PLZZZ HELP!!! What is the main difference between a permanent magnet and a temporary magnet?

2 answers:

HACTEHA [7]3 years ago

9 0

The domains in a temporary magnet easily lose alignment, but the domains in a permanent magnet keep their alignment.

Oksanka [162]3 years ago

9 0

Answer: The correct answer is "The domains in a temporary magnet easily lose alignment, but the domains in a permanent magnet keep their alignment".

Explanation:

Permanent magnet: Bar magnet is the example of the permanent magnet.

The poles of the temporary magnet can not be changed. The strength of the magnetic field can not be increased or decreased. The domains of the permanent are permanent aligned.

Temporary magnet: Electromagnet is the example of the temporary magnet.

The poles of the temporary magnet can be changed. The strength of the magnetic field can be increased or decreased. If the current will not flow in the electromagnet then it will easily loose its magnetism. The domains in a temporary magnet easily loose alignment.

Therefore, the correct difference between a permanent and a temporary magnet is "The domains in a temporary magnet easily lose alignment, but the domains in a permanent magnet keep their alignment".

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For a wire has a circular cross section with a radius of 1.23mm.

Mila [183]

Answer:

$5.731\times 10^{-5}\ m/s$

Decrease

Explanation:

I = Current = 3.7 A

e = Charge of electron = $1.6\times 10^{-19}\ C$

n = Conduction electron density in copper = $8.49\times 10^{28}\ electrons/m^3$

$v_d$ = Drift velocity of electrons

r = Radius = 1.23 mm

Current is given by

$I=neAv_d\\\Rightarrow v_d=\dfrac{I}{neA}\\\Rightarrow v_d=\dfrac{3.7}{8.49\times 10^{28}\times 1.6\times 10^{-19}\times \pi (1.23\times 10^{-3})^2}\\\Rightarrow v_d=5.731\times 10^{-5}\ m/s$

The drift speed of the electrons is $5.731\times 10^{-5}\ m/s$

$v_d=\dfrac{I}{neA}$

From the equation we can see the following

$v_d\propto \dfrac{1}{n}$

So, if the number of conduction electrons per atom is higher than that of copper the drift velocity will decrease.

5 0

3 years ago

Kiera, a 330 N girl, steps in water that someone spilt on the floor. The coefficient of kinetic friction between Kiera and the f

shutvik [7]

Answer:

<em>The force of kinetic friction between Kiera and the floor is 9.24 N</em>

Explanation:

<u>Friction Force</u>

When an object is moving and encounters friction in rough surfaces, it loses acceleration and/or velocity because the friction force opposes motion.

The friction force when an object is moving on a horizontal surface is calculated by:

$Fr=\mu N$

Where μ is the coefficient of static or kinetics friction and N is the normal force.

If no forces other then the weight and the normal are acting upon the y-direction, then the weight and the normal are equal in magnitude:

N = W

Thus, the friction force is:

$Fr=\mu W$

Kiera, the W=330 N girl steps in water that has a coefficient of friction of μ=0.028 with the floor.

The kinetic friction force is:

Fr = 0.028*330

Fr = 9.24 N

The force of kinetic friction between Kiera and the floor is 9.24 N

3 0

3 years ago

A rope breaks when the tension reaches 205 N. What is the maximum speed at which it can swing a 0.477 kg mass in a circle of rad

jekas [21]

Answer:

Maximum velocity will be 17.651 m /sec

Explanation:

We have given a rope breaks when tension reaches 205 N

Mass m = 0.477 kg

Radius of the circle r = 0.725 m

Tension in the rope is given by

$T=\frac{mv^2}{r}$

$205=\frac{0.477\times v^2}{0.725}$

$0.477v^2=148.625$

$v^2=311.5828$

v = 17.651 m /sec

8 0

4 years ago

A car initially at rest undergoes uniform acceleration for 6.32 seconds and covers a distance of 120 meters. What is the approxi

Verizon [17]

Using kinematic equation s=ut + 1/2 at^2(u = initial velocity=0, s=120m, t= 6.32s), 120 = 0(t) + 1/2 a(6.32)^2. a = 120x2/(6.32)^2 = 6m/s^2.

3 0

3 years ago

Read 2 more answers

Mass is a measure of the quantity of matter in an object.<br> a. True<br> b. False

marishachu [46]

A. True

It is true that mass is a measure of the quantity of matter in an object.

3 0

4 years ago