All categories

2 years ago

PLZZZ HELP!!! What is the main difference between a permanent magnet and a temporary magnet?

Physics

2 answers:

HACTEHA [7]2 years ago

9 0

The domains in a temporary magnet easily lose alignment, but the domains in a permanent magnet keep their alignment.

Oksanka [162]2 years ago

9 0

Answer: The correct answer is "The domains in a temporary magnet easily lose alignment, but the domains in a permanent magnet keep their alignment".

Explanation:

Permanent magnet: Bar magnet is the example of the permanent magnet.

The poles of the temporary magnet can not be changed. The strength of the magnetic field can not be increased or decreased. The domains of the permanent are permanent aligned.

Temporary magnet: Electromagnet is the example of the temporary magnet.

The poles of the temporary magnet can be changed. The strength of the magnetic field can be increased or decreased. If the current will not flow in the electromagnet then it will easily loose its magnetism. The domains in a temporary magnet easily loose alignment.

Therefore, the correct difference between a permanent and a temporary magnet is "The domains in a temporary magnet easily lose alignment, but the domains in a permanent magnet keep their alignment".

You might be interested in

PLEASE HELP ASAP!!!

musickatia [10]

Answer:

22.2 W

Explanation:

First of all, we calculate the work done by moving the wagon, using the formula:

$W=Fdcos \theta$

where

F = 20 N is the magnitude of the force

d = 1000 m is the displacement of the wagon

$\theta=0^{\circ}$ is the angle between the direction of the force and of the displacement (assuming the force is applied in the direction of motion)

Substituting, we find

$W=(20)(1000)=20,000 J$

Now we can find the power generated, which is equal to the ratio between the work done and the time taken:

$P=\frac{W}{t}$

where

W = 20,000 J

t = 15 min = 900 s

Substituting,

$P=\frac{20000}{900}=22.2 W$

And the same value in Joules/second (remember that 1 Watt = 1 Joule/second)

5 0

2 years ago

Karla Ayala pulls a sled on an icy road (dangerous!). Because of Karla's pull, the tension force is 151 N, and the rope makes a

skelet666 [1.2K]

Answer:

W = 1418.9 J = 1.418 KJ

Explanation:

In order to find the work done by the pull force applied by Karla, we need to can use the formula of work done. This formula tells us that work done on a body is the product of the distance covered by the object with the component of force applied in the direction of that displacement:

W = F.d

W = Fd Cosθ

where,

W = Work Done = ?

F = Force = 151 N

d = distance covered = 10 m

θ = Angle with horizontal = 20°

Therefore,

W = (151 N)(10 m) Cos 20°

6 0

2 years ago

19. After a snowstorm, you put on your frictionless skis and tie a rope to the back of your friend’s truck. Your total mass is 7

Kisachek [45]

Explanation:

It is given that,

Total mass is 70 kg

The truck exerts a constant force of 20 N.

Then the net force is given by :

F = ma

a is acceleration of rider

$a=\dfrac{F}{m}\\\\a=\dfrac{20}{70}\\\\a=\dfrac{2}{7}\ m/s^2$

Initial velocity of rider is 0. So, using equation of kinematics to find the final velocity as :

$v=u+at\\\\v=at\\\\v=\dfrac{2}{7}\times 15\\\\v=4.28\ m/s$

Since, 1 m/s = 2.23 mph

4.28 m/s = 9.57 mph

So, the speed of the rider is 4.28 m/s or 9.57 mph.

5 0

2 years ago

How does the current in a circuit change if the resistance is doubled? The current is halved. The current is doubled. The curren

Inessa05 [86]

Answer:

The current is halved

Explanation:

The relationship between the current and the resistance is given by Ohm's Law, as follows:

$V = IR\\I = \frac{V}{R}$

where,

V = Voltage

I = Current

R = Resistance

Therefore, if we double the resistance:

$I' = \frac{V}{2R}\\\\I' = \frac{1}{2}I$

Hence the correct option is:

<u>The current is halved</u>

7 0

2 years ago

Read 2 more answers

Why is a protective apron or lab coat important to use when working with acids?

Kipish [7]

Answer:

Acids break down fabrics and can cause burns if the acids are strong.

Explanation:

A protective apron or lab coat is important when working with acids because acids break down fabrics and can cause burns if the acids are strong.

An acid is a substance that interacts with water to produce excess hydroxonium ions in an aqueous solution.
A strong acid ionizes completely in solution.
When they come in contact with a fabric, they break them down violently.
So, if they come in contact with the skin, it causes a violent break down of body tissues.
The apron acts a protective layer.

4 0

2 years ago

Read 2 more answers