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KIM [24]
4 years ago
10

How does work affect energy between objects so it can cause a change in the form of energy? Work transfers energy. Work changes

energy. Work increases energy. Work decreases energy.
Physics
2 answers:
Pavel [41]4 years ago
7 0

Answer: Work can transfer energy between objects and cause a change in the amount of total energy. Work can transfer energy between objects and cause a change in the form of energy. ... When a spring is compressed, the energy changes from kinetic to potential.

Aleksandr-060686 [28]4 years ago
6 0

Answer:

work can transfer energy

Explanation:

sense there is a ton of effort in work it can accumulate energy. physical and thermal energy. :)

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A 235 kg motorcycle moves with a velocity of 7 m/s. What's it's kenetic energy?
antiseptic1488 [7]
The non-relativistic formula for low speed  v < 0.1c is:

K.E = 0.5mv^2 = 0.5 * 235 * (7)^2 = 5757.5 J
7 0
4 years ago
A rocket ship leaves Earth's atmosphere. Its initial velocity is less than its final velocity. What is this an example of?
77julia77 [94]
I believe this would be an example of positive acceleration as the initial velocity of the rocket is less than the final velocity, indicating that the rocket is accelerating and thus is positive.
6 0
3 years ago
Read 2 more answers
A 2-kg object is moving 6 m/s in a horizontal direction.
german

Answer: A) O N

Explanation:

An object in motion will maintain its state of motion. The presence of an unbalanced force changes the velocity of the object.

4 0
3 years ago
Can earthquakes with a magnitude between 3.0 and 6.0 produce high intensity levels?
laiz [17]
3.0 typically is only felt by people who are resting or on the up stairs of buildings. 6.0 is more intense. I would say a 6.0 can produce high intensity levels. A 6.0 can damage buildings of good design and structure. Damagable in poorly built or badly designed structures. Some chimneys may be broken.
5 0
3 years ago
A metal rod has a length of 123. cm at 200°C. At what temperature will the length be 92.6 cm if the coefficient of linear expans
mestny [16]

Answer:

\theta_{2} = 15400^0 C

Explanation:

The formula for linear expansivity, \alpha = \frac{l_{2} - l_{1}  }{l_{1} ( \theta_{2}  - \theta_{1} )}

original length, l₁ = 123 cm = 1.23 m

final length, l₁ = 92.6 cm =0.926 m

original temperature, θ₁ = 200°C

Linear expansivity, α = 2 * 10⁻⁵ °C⁻¹

Putting these values into the formula:

2 * 10^{-5}  = \frac{1.23 - 0.926  }{l_{1} ( \theta_{2}  -200 )}\\ \theta_{2}  -200 = \frac{0.304}{2 * 10^{-5} } \\\theta_{2} = 15200 + 200\\\theta_{2} = 15400^0 C

7 0
3 years ago
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