For this item, we need to assume that air behaves like that of an ideal gas. Ideal gases follow the ideal gas law which can be written as follow,
PV = nRT
where P is the pressure,
V is the volume,
n is the number of mols,
R is the universal gas constant, and
T is temperature
In this item, we are to determine first the number of moles, n. We derive the equation,
n = PV /RT
Substitute the given values,
n = (1 atm)(5 x 10³ L) / (0.0821 L.atm/mol.K)(0 + 273.15)
n = 223.08 mols
From the given molar mass, we calculate for the mass of air.
m = (223.08 mols)(28.98 g/mol) = 6464.9 g
<em>ANSWER: 6464.9 g</em>
Answer:
273.9 fathom
Explanation:
Fathom (ftm) and rod are the units of length used in the imperial and the U.S. customary systems.
Fathom is an unit used for the measurement of depth of water. It is equal to 1.8288 m.
Rod, also known as perch or pole, is equal to 5.0292 m.
∵ 1 fathom = 0.364 rod
and 1 rod = 2.75 fathom
∴ 99.6 rod = 99.6 × 2.75 fathom = 273.9 fathom
<u>Therefore, maximum depth of Lake Tahoe = 99.6 rod = 273.9 fathom</u>
Answer:
S²⁻(aq) + Cr²⁺(aq) ⇄ CrS(s)
Explanation:
The molecular equation includes all the species in the molecular form. Usually, it is useful to write this first to balance the equation. This is a double displacement reaction.
K₂S(aq) + Cr(NO₃)₂(aq) ⇄ 2 KNO₃(aq) + CrS(s)
The full ionic equation includes all ions and the species that no dot dissociate in water.
2 K⁺(aq) + S²⁻(aq) + Cr²⁺(aq) + 2 NO₃⁻(aq) ⇄ 2 K⁺(aq) + 2 NO₃⁻(aq) + CrS(s)
The net ionic equation includes only those ions that participate in the reaction and the species that do not dissociate in water.
S²⁻(aq) + Cr²⁺(aq) ⇄ CrS(s)
The concentration of the zinc acetate, Zn(C₂H₃O₂) solution is 1.067 M
- We'll begin by calculating the number of mole in 20.5 g of Zn(C₂H₃O₂)₂
Mass of Zn(C₂H₃O₂)₂ = 20.5 g
Molar mass of Zn(C₂H₃O₂)₂ = 65 + 2[(12×2) + (3×1) + (16×2)]
= 65 + 2[59]
= 183 g/mol
<h3>Mole of Zn(C₂H₃O₂)₂ =? </h3>
Mole = mass / molar mass
Mole of Zn(C₂H₃O₂)₂ = 20.5 / 183
<h3>Mole of Zn(C₂H₃O₂)₂ = 0.112 mole </h3>
- Finally, we shall determine concentration of Zn(C₂H₃O₂). This can be obtained as follow:
Mole of Zn(C₂H₃O₂)₂ = 0.112 mole
Volume = 105 mL = 105 / 1000 = 0.105 L
<h3>Concentration of Zn(C₂H₃O₂)₂ =? </h3>
Concentration = mole / Volume
Concentration of Zn(C₂H₃O₂)₂ = 0.112 / 0.105
<h3>Concentration of Zn(C₂H₃O₂)₂ = 1.067 M</h3>
Therefore, the concentration of the zinc acetate, Zn(C₂H₃O₂) solution is 1.067 M
Learn more: brainly.com/question/25511880
The volume of CO2 prodiced when 12 mL of CH4 and 8 mL of C4H10 is burnt is 56 mL.
<h3>What is the equation of the reaction?</h3>
The equation of the combustion of C2H6, CH4, C4H10, and C3H8 gases are given below:
2 C2H6 + 7 O2 ---> 4 CO2 + 6 H20
C3H8 + 5 O2 ---> 3 CO2 + 4 H20
CH4 + 2 O2 ----> CO2 + 2 H2O
2 C4H10 + 13 O2 ---> 8 CO2 + 10 H2O
X moles of C2H6 will produce 2X moles of CO2
Y moles of C3H8 will produce 3Y moles of CO2
Thus;
X + Y = 20 mL
X =20 - Y ---(1)
2X + 3Y = 52 mL ---(2)
Solving for X by substituting in (2)
2 (20 - Y) + 3Y = 52
40 - 2Y + 3Y = 52
Y = 12 mL
Then X = 8 mL
Volume of CO2 produced when 12 mL of CH4 and 8 mL of C4H10 is burnt = (12 × 2 + 8 × 4) = 56 mL
Therefore, the volume of CO2 produced is 56 mL.
Learn more about moles of gas and volume at: brainly.com/question/23883946
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