Answer:
Explanation:
From the question we are told that
The number of moles of is
The volume of is =
The concentration of
The for is
The number of moles of is mathematically evaluated as
substituting values
The equation for this reaction is
⇄
From this equation we can mathematically evaluate the limiting reactant as
For
For
Hence the Limiting reactant is
At the initial the number of moles of produced is mathematically evaluated as
The remaining amount of is
Now the reaction is complete
The number of moles of = 0 moles
For this kind of reaction after the complex solution(which is at equilibrium) has been formed they disassociate again ( which is also at equilibrium )
Let the number of moles of after disassociation be z
The the number of moles of after disassociation be 0.9 + 6z
The 6 is from the reaction equation
The the number of moles of after disassociation be
Now the equilibrium constant for this reaction is
The powers of these concentration is are their moles
substituting value
Since the back reaction is very little so we can neglecting subtracting it from the moles of and adding it to the number of moles of
Because it won't affect the value of z obtained
So the number of moles of at equilibrium is
The concentration of is mathematically represented as
The moles of is =
The concentration of is mathematically represented as