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4 years ago

A graphic designers is not a visual artist. True False

2 answers:

Colt1911 [192]4 years ago

5 0

This answer is false. A visual artist is defined as someone involved in the arts of painting, sculpting, photography, etc, as opposed to music, drama, and literature. A visual artist is in the form of making somthing more visable. So, a graphic designer is a visual artist.

Mandarinka [93]4 years ago

5 0

False. I’m so sorry if im wrong! I’m no tell really good at them I tried! Like I said I’m sorry! :(

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Which of these pollutants is transferred from soil to water by organic pesticides and fertilizer runoff from farms?

Sedbober [7]

I would say your answer to this question would be D

4 0

3 years ago

Read 2 more answers

Ezra (m = 20.0 kg) has a tire swing and wants to swing as high as possible. He thinks that his best option is to run as fast as

Dmitriy789 [7]

Answer:

a) $v=5.6725\,m.s^{-1}$

b) $h= 1.6420\,m$

Explanation:

Given:

mass of the body, $M=20\,kg$

mass of the tyre, $m=10\,kg$

length of hanging of tyre, $l=3.5m$

distance run by the body, $d=10m$

acceleration of the body, $a=3.62m.s^{-2}$

(a)

Using the equation of motion :

$v^2=u^2+2a.d$ ..............................(1)

where:

v=final velocity of the body

u=initial velocity of the body

here, since the body starts from rest state:

$u=0m.s^{-1}$

putting the values in eq. (1)

$v^2=0^2+2\times 3.62 \times 10$

$v=8.5088\,m.s^{-1}$

Now, the momentum of the body just before the jump onto the tyre will be:

$p=M.v$

$p=20\times 8.5088$

$p=170.1764\,kg.m.s^{-1}$

Now using the conservation on momentum, the momentum just before climbing on the tyre will be equal to the momentum just after climbing on it.

$(M+m)\times v'=p$

$(20+10)\times v'=170.1764$

$v'=5.6725\,m.s^{-1}$

(b)

Now, from the case of a swinging pendulum we know that the kinetic energy which is maximum at the vertical position of the pendulum gets completely converted into the potential energy at the maximum height.

So,

$\frac{1}{2} (M+m).v'^2=(M+m).g.h$

$\frac{1}{2} (20+10)\times 5.6725^2=(20+10)\times 9.8\times h$

$h\approx 1.6420\,m$

above the normal hanging position.

3 0

3 years ago

a car is moving down the street at 55km/h. a child suddenly runs into the street. If it takes the driver 0.75 seconds to react a

Lelechka [254]

11.46 meters

55 km/h = ? m/s
55 km/h × 1000 (meters per km) = 55,000 m/h
55,000 m/h ÷ 3,600 (seconds in an hour) = 15.28 m/s
15.28 m/s × 0.75 s = 11.46 m

3 0

4 years ago

A 615 N student standing on a scale in an elevator notices that the scale reads 645 N. From this information, the student knows

BARSIC [14]

Answer:

The elevator must be moving upward.

Explanation:

During the motion of an elevator, the weight of the person deviates from his or her actual weight. This temporary weight during the motion is referred to as "Apparent Weight". So, when the elevator is moving downward, the apparent weight of the person becomes less than his or her actual weight.

On the other hand, for the upward motion of the elevator, the apparent weight of the person becomes more than the actual weight of that person.

Since the apparent weight (645 N) of the student, in this case, is greater than the actual weight (615 N) of the student.

<u>Therefore, the elevator must be moving upward.</u>

8 0

3 years ago

What is the shape of the trajectory that a charged particle follows in a uniform magnetic field?

Darya [45]

Answer:

circle

Explanation:

5 0

3 years ago