Answer:
A. The cart will move to the left
Explanation:
Right has more force acting on the cart than the left
Answer:
The principle of superposition states that when a number of charges are interacting, the net electrostatic force a given charge is the vector sum of the forces exerted on it due to all other charges. The force between two charges is not affected by the presence of other charges.
Answer:
So, you're going to need the equation ρ = ρo [1 + α(T-To)]
1.59x10^-8 ohms*m is your ρo because that is measured at your reference temperature (To), 20◦C. T is your 6◦C and α is 0.0038(◦C)−1. So, using that you solve for ρ. If you keep up with the units though, you notice it comes out to be ohms*m and that isn't what you want.
So, the next equation you need is J=σE where E is your electric field (3026 V/m) and σ is the electrical conductivity which is the inverse of your answer you got in the previous equation. So find the inverse of that answer and multiply it by your electric field and that will give you the current density.
I hope this helps!
Explanation:
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Answer: Decreasing the distance between Hox and Blox, increasing the mass of Hox, or increasing the mass of Hox and Blox.
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Explanation:
According to the law of universal gravitation:
Where:
is the module of the attraction force exerted between both planets
is the universal gravitation constant.
and
are the masses of both planets.
is the distance between both planets.
As we can see, the gravity force is directly proportional to the mass of the bodies and inversely proportional to the square of the distance that separates them.
In other words:
If we decrease the distance between both planets (Hox and Blox), the gravitational pull between them will increase.
On the other hand, if we keep the distance between Hox and Blox, but we increase the mass of one of them, or increase the mass of both, the gravitational pull between them will also increase.
The current is defined as the ratio between the charge Q flowing through a certain point of a wire and the time interval,

:

First we need to find the net charge flowing at a certain point of the wire in one second,

. Using I=0.92 A and re-arranging the previous equation, we find

Now we know that each electron carries a charge of

, so if we divide the charge Q flowing in the wire by the charge of one electron, we find the number of electron flowing in one second: