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3 years ago

5

What environmental factor could be altered in order to increase the initial reaction rate in experiment one if the initial conce

ntrations of the reactants remained the same?

1 answer:

nadezda [96]3 years ago

7 0

Idk lolololololololololol

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How many grams of baf2 are in 3.7 moles of baf2

Mice21 [21]

To convert moles to gram multiply 3.7 moles of BaF2 to the molar mass of BaF2

BaF2 molar mass = 175.326

3.7 moles x 175.326g = 648.70g BaF2

8 0

4 years ago

One of the waste byproducts of a nuclear reactor using uranium-235 is strontium-90 with half-life of about 28 years. If we have

e-lub [12.9K]

Answer:

(a) 140 years

(b) 3.125 pounds

Explanation:

<u>QuestIons</u>

(a) How long is five half-life

(b) How much radioactive strontium is left after five half-life

Given that:

Half-life is about 28 years; &

There are 100 pounds of this radioactive waste

Five half-life will be;

= 28 × 5

= 140 years

The amount of radioactive remaining after five half-life is:

$= 100 \times( \dfrac{1}{2}) ^5$

= 100 × 0.03125

= 3.125 pounds

5 0

3 years ago

Calculate the mass (in grams) of methylene bluecrystals that you must weigh in order to make 100.0mL of 1.25 × 10-5mol/L methyle

mario62 [17]

<u>Answer:</u> The mass of methylene blue that must be weighed is $3.99\times 10^{-4}g$

<u>Explanation:</u>

To calculate the mass of solute, we use the equation used to calculate the molarity of solution:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

We are given:

Molarity of solution = $1.25\times 10^{-5}M$

Molar mass of methylene blue = 319.85 g/mol

Volume of solution = 100.0 mL

Putting values in above equation, we get:

$1.25\times 10^{-5}M=\frac{\text{Mass of methylene blue}\times 1000}{319.85\times 100.0}\\\\\text{Mass of methylene blue}=\frac{1.25\times 10^{-5}\times 319.85\times 100.0}{1000}=3.99\times 10^{-4}g$

Hence, the mass of methylene blue that must be weighed is $3.99\times 10^{-4}g$

4 0

3 years ago

In a titration experiment a student uses 1.4 m hbr solution and the indicator phenolphthalein to determine the concentration of

Likurg_2 [28]

The question is incomplete. Complete question is attached below:
...........................................................................................................................

Answer:
Given: conc. of HBr = 1.4 M
Volume of HBr = 15.4 mL
Volume of KOH = 22.10 mL

We know that, M1V1 = M2V2
(HBr) (KOH)

Therefore, M2 = M1V1/V2
= 1.4 X 15.4/22.10
= 0.9756 M

Concentration of KOH is 0.9756 M.

3 0

3 years ago

Read 2 more answers

During which phase change does water release the most heat energy?

miss Akunina [59]

The phase change that releases the most energy is deposition, when gas turns into a solid. It takes the absorption of energy to melt a solid into a liquid, and even more energy to vaporize the liquid into a gas. Hence, the reverse process (from solid to gas) will result in the greatest release of energy.

4 0

3 years ago