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blondinia [14]
4 years ago
12

Convert 95 kilograms into centigrams

Chemistry
1 answer:
leonid [27]4 years ago
8 0
The Answer is 9.5e+6
1 kilogram= 100000 <span>centigrams</span>
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What is the mass of 8.87 x 10^24 atoms of carbon?<br><br> PLEASE HELP!!
stiks02 [169]

Answer: 177g

Explanation:

Aw 12 = 6.02214076*10^23 atoms

mass = 12*88.70^23/6.022*10^23

4 0
3 years ago
If 35 mL of 0.10 Macid solution is neutralized by 21.8 mL of a basic solution, what is the molarity
expeople1 [14]
I don’t understand this one sorry
5 0
4 years ago
The number of Joules needed to raise the temperature of 10 grams of water from 20°C to 30°C is
e-lub [12.9K]

Answer:

418 Joules

Explanation:

Q=10(4.18)(10)

6 0
3 years ago
How many grams of molybdenum(Mo) are in 2.68E24 atoms of Mo?
loris [4]
<h3>Answer:</h3>

427 g Mo

<h3>General Formulas and Concepts:</h3>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right
<h3>Explanation:</h3>

<u>Step 1: Define</u>

2.68E24 atoms Mo or 2.68 × 10²⁴ atoms Mo

<u>Step 2: Identify Conversions</u>

Avogadro's Number

Molar Mass of Mo - 95.94 g/mol

<u>Step 3: Convert</u>

<u />2.68 \cdot 10^{24} \ atoms \ Mo(\frac{1 \ mol \ Mo}{6.022 \cdot 10^{23} \ atoms \ Mo} )(\frac{95.94 \ g \ Mo}{1 \ mol \  Mo} ) = 426.966 g Mo

<u>Step 4: Check</u>

<em>We are given 3 sig figs. Follow sig fig rules and round.</em>

426.966 g Mo ≈ 427 g Mo

3 0
3 years ago
Round off each measurement to the number of significant figures shown in parentheses.
Wewaii [24]

We have to round off each measurement to the number of significant figures.

The correct answers are: 265.9, 0.00045 and 65 respectively.

265.991 when expressed in 4 significant figure it rounds off as 265.9 because  265.9 represents the value 265.991.

0.0004513 when expressed in 2 significant figure it rounds off as 0.00045 because zero before and after decimal are not significant.

6593 when expressed in 2 significant figure it rounds off as 65.


6 0
3 years ago
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