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Shalnov [3]
4 years ago
10

Why are some rocks more easily weathered than other rocks

Chemistry
1 answer:
dmitriy555 [2]4 years ago
3 0
Because of their atom's composition. some are naturally packed closer together and stronger and more durable, while others tend to be more loose and breakable and/or weaker/less durable. also with how their atoms are composed is how the atoms interact with each other/ how they share or give or take electrons.
You might be interested in
Solid iron(III) oxide reacts with hydrogen gas to form solid iron and liquid water.
Marrrta [24]

Hello, this question is incomplete. The complete question would be:

"Write the balanced chemical equation for the following reaction.

Solid iron(III) oxide reacts with hydrogen gas to form solid iron and liquid water"

Answer:

Fe2O3 + 3 H2 = 2 Fe + 3 H2O

Explanation:

In a chemical reaction, the structure of atoms as chemical elements is unchanged. Atoms in one element do not become atoms in another element. There is also no loss or creation of new atoms. The number of atoms of the reagents must be equal to the number of atoms of the products. When this happens, we say that the chemical equation is balanced.

For this reason, we can state that the balanced chemical reaction where solid iron (III) oxide reacts with hydrogen gas to form solid iron and liquid water would be:

<em>Fe2O3 + 3 H2 = 2 Fe + 3 H2O </em>

5 0
3 years ago
Given the balanced equation 2C4H10 + 13O2 → 8CO2 + 10H2O, how many moles of CO2 are produced when 14.9g of O2 are used?
Anna [14]

Answer: The number of moles of CO_2 produced are, 0.287 moles.

Explanation : Given,

Mass of O_2 = 14.9 g

Molar mass of O_2 = 32 g/mol

First we have to calculate the moles of O_2

\text{Moles of }O_2=\frac{\text{Given mass }O_2}{\text{Molar mass }O_2}

\text{Moles of }O_2=\frac{14.9g}{32g/mol}=0.466mol

Now we have to calculate the moles of CO_2

The balanced chemical equation is:

2C_4H_{10}+13O_2\rightarrow 10H_2O+8CO_2

From the reaction, we conclude that

As, 13 mole of O_2 react to give 8 moles of CO_2

So, 0.466 mole of O_2 react to give \frac{8}{13}\times 0.466=0.287 mole of CO_2

Therefore, the number of moles of CO_2 produced are, 0.287 moles.

3 0
3 years ago
I have a sample of galena. It appears there may be some gold in it. It is a piece of raw ore so I took it to a metallurgist and
Lubov Fominskaja [6]

Yes it is possible

Explanation:

Galena and gold can become encrusted together. They can form together in the same geologic setting.

  • Gold usually occurs freely in nature uncombined with other atoms.
  • Galena is the largest ore of lead.
  • Both minerals can become twinned under appropriate geologic conditions.
  • They are usually seen in pegmatitic intrusions in a rock body as product of late stage melt crystallization.

learn more:

Renewable resources brainly.com/question/4344417

#learnwithBrainly

7 0
3 years ago
153 mL of 2.5 M HF is reacted with an excess of Ca(OH)2. How many grams of CaF2 will be produced?
Delvig [45]

Answer:

15 g

Explanation:

Data given:

amount of  HF  = 153 mL  2.5 M HF

amount of Ca(OH)₂ = Excess

grams of CaF₂ = ?

Reaction Given:

                2HF + Ca(OH)₂ ------→ 2H₂O + CaF₂

Solution:

First we have to find number of moles of HF in 153 mL of 2.5 M HF

For this we will use following formula

               Molarity = moles of solute / liter of solution

Rearrange above equation

               moles of solute =  Molarity x liter of solution . . . . . (1)

Put values in above equation (1)

               moles of solute =  2.5 x 1 L

              moles of solute =  2.5

So,

we come to know that there are 2.5 moles of solute (HF) in 1 L of solution

Now how many moles of solute will be present in 153 ml of solution

Convert 153 mL to Liter

1000 mL = 1 L

153 mL = 153/1000 = 0.153 L

Apply Unity Formula

                       2.5 moles HF ≅ 1 L solution

                        X moles of HF ≅ 0.153 L solution

              moles of HF = 2.5 moles x 0.153 mL solution / 1 L solution

              moles of HF =  0.383 moles

  • So, 153 mL contains 0.383 moles of HF

Now Look at the reaction:

                     2HF + Ca(OH)₂ ------→ 2H₂O + CaF₂

                    2 mol                                          1 mol

From the reaction we come to know that 2 moles of HF gives 1 mole of CaF₂ then how many moles of CaF₂  will be produced from o.383 moles of HF

Apply Unity Formula

                       2 moles HF ≅ 1 mole of CaF₂

                       0.383 moles of HF ≅ X moles of CaF₂

              moles of CaF₂  = 0.383 moles x 1 mole / 2 mol

              moles of CaF₂ =  0.192 moles

  • So, 0.192 moles of  CaF₂ will be produced by 0.383 moles of HF

Now we will find mass of 0.192 moles of  CaF₂

Formula will be used

          mass in grams = no. of moles x molar mass . . . . . . . (2)

molar mass of CaF₂ = 40 + 2(19)

molar mass of CaF₂ = 40 + 38 =  78 g/mol

Put values in eq. 2

        mass in grams = 0.192 x 78 g/mol

        mass in grams = 14.976 g

rounding the value

          mass in grams = 15 g

So,153 mL of 2.5 M HF is reacted with an excess of Ca(OH)₂ will produce 15 g of CaF₂.

6 0
4 years ago
A metal oxide reacts chemically with water to form a base in the reaction shown below. If the temperature of the metal oxide and
Alla [95]

increase the rate of chemical change.

Explanation:

The reaction of the metal oxide with water to form a base in the presence of a spike in temperature will lead to an increase in the rate of chemical change.

Temperature change has considerable effect on reaction rates.

  • Temperature is directly proportional to the average kinetic energy of reacting particles.
  • Reaction rates varies directly with a spike in temperature.
  • It has been known that for every 10°C rise in temperature, above the room temperature, reaction rates become double or tripled.
  • Temperature increases the kinetic energy of each of the reacting particles.
  • Many of the reacting particles also acquires an energy greater than or equal to the activation energy of the reaction.
  • The frequency of ordinary collisions and effective collisions per unit time increases.

Learn more;

Activation energy brainly.com/question/3930233

#learnwithBrainly

6 0
3 years ago
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