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2 years ago

9

A capacitor has plates of area 1.64 * 10 ^ - 3 * m ^ 2 . To create a capacitance of 2.38 * 10 ^ - 9 * F , how far apart should t

he plates be? [?]*10^ [?] m

1 answer:

lesya692 [45]2 years ago

6 0

Answer:

6.1 * 10^-6

Explanation:

Acellus

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A paper airplane with mass 0.1 kg is flying 1.5 m above the ground with a speed of 2 m/s. What is the total mechanical energy of

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Total mechanical energy = kinetic energy + potential energy
E = KE + PE
E = ½mv² + mgh
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E = 0.2 J + 1.47 J
E = 1.67 J

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What do understand by the efficiency of a machine? By using a block and tackel a man can raise a load of 720 N by an effort of 1

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3 years ago

Technician A says that a tire will increase or decrease approximately 1 psi for each 10°F change of temperature. Technician B sa

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Technician A

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A mass free to vibrate on a level, frictionless surface at the end of a horizontal spring is pulled 35 cm from its equilibrium p

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Answer:

0.67 s

Explanation:

This is a simple harmonic motion (SHM).

The displacement, $x$ , of an SHM is given by

$x = A\cos(\omega t)$

A is the amplitude and $\omega$ is the angular frequency.

We could use a sine function, in which case we will include a phase angle, to indicate that the oscillation began from a non-equilibrium point. We are using the cosine function for this particular case because the oscillation began from an extreme end, which is one-quarter of a single oscillation, when measured from the equilibrium point. One-quarter of an oscillation corresponds to a phase angle of 90° or $\frac{\pi}{4}$ radian.

From trigonometry, $\sin A =\cos B$ if A and B are complementary.

At $t = 0$ , $x = 3.5$

$3.5 = A\cos(\omega \times0)$

$A =3.5$

So

$x = 3.5\cos(\omega t)$

At $t = 0.12$ , $x = 1.5$

$1.5 = 3.5\cos(0.12\omega)$

$\cos(0.12\omega)=\dfrac{1.5}{3.5}=0.4286$

$0.12\omega =\cos^{-1}0.4286$

$0.12\omega = 1.13$

$\omega = 9.4$

The period, $T$ , is related to $\omega$ by

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