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aliina [53]
2 years ago
9

A capacitor has plates of area 1.64 * 10 ^ - 3 * m ^ 2 . To create a capacitance of 2.38 * 10 ^ - 9 * F , how far apart should t

he plates be? [?]*10^ [?] m
Physics
1 answer:
lesya692 [45]2 years ago
6 0

Answer:

6.1 * 10^-6

Explanation:

Acellus

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olganol [36]

Answer:

A  mercury barometer is a device use to measure stomspheric pressure and is constructed as following:

  • A mercury barometer requires a tube which has one close end, and one open end.
  • Tube is placed upside down in a beaker in such a way so that one end open in the beaker and the other remain outside of the beaker.
  • The barometric liquid (mercury) is then filled in the tube by pouring mercury liquid in the beaker.

The position of tube creates vacuum between the closed end of the tube and liquid surface and the Mercury has high density that is why used as the liquid to measure pressure.

4 0
3 years ago
What is a hypothesis?
Likurg_2 [28]

Answer:

A

Explanation:

a statement that can be tested through the scientific method

4 0
2 years ago
An astronaut exploring a distant solar system lands on an unnamed planet with a radius of 2530 km. When the astronaut jumps upwa
Natali [406]

Answer:

1.38*10^18 kg

Explanation:

According to the Newton's law of universal gravitation:

F=G*\frac{m_a*m_p}{r^2}

where:

G= Gravitational constant (6.674×10−11 N · (m/kg)2)

ma= mass of the astronaut

mp= mass of the planet

F=m_a.a\\(v_f )^2=(v_o)^2+2.a.\Delta y\\\\a=\frac{(v_f)^2-(v_o)^2}{2.\Delta y}\\\\a=\frac{(0)^2-(4.29m/s)^2}{2.0.64m}=14.38m/s^2\\\\F=m_a*14.38m/s^2

so:

m_a*14.38m/s^2=(6.674*10^{-11}N.(m/kg)^2)*\frac{m_a.m_p}{(2.530*10^3m)^2}\\m_p=\frac{14.38m/s^2(2.530*10^3m)^2}{(6.674*10^{-11}N.(m/kg)^2)}\\\\m_p=1.38*10^{18}kg

7 0
3 years ago
i like honey but when u put it on your feet it sticks to the ground. how do i avoid the stickyness of honey when i want to clean
Gre4nikov [31]

Answer:

please stop asking questions

Explanation:

6 0
3 years ago
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k0ka [10]

Answer:

The required diagram is shown in the figure. When an object is placed in front of the convex lens, i.e., between 2F

1

and F

1

, its image is formed beyond 2F

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on the other side of the lens. The image is real, inverted and enlarged.

solution

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3 years ago
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