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Vanyuwa [196]
4 years ago
14

Write down the reaction schemes including intermediate if any to show the preparation in aqueous solution for each of the stereo

isomers of [Pt (nh3)(no2)Cl2]​

Chemistry
1 answer:
Ann [662]4 years ago
4 0

Answer:

<em>Scheme attached</em>

Explanation:

<em>Trans</em> effect is involved in this synthesis. As in the reactions of planer metal complexes, trans effect dominates the stereo-chemistry of the product.

<em>Trans</em> effect

The role of the element present in trans position to the element to be substituted is called the trans effect. The nature of the ligand in trans position effects the substitution, if it has high <em>trans</em> effect it make the substitution difficult.

So when we attach NH₃ first to the ligand it make the trans substitution difficult, hence <em>cis</em> product will be formed.

As NO₂ has very low <em>trans</em> effect, so it doesn't effect the substitution and the <em>trans</em> product will be formed as usual.

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Sulfur trioxide, SO3 , is produced in enormous quantities each year for use in the synthesis of sulfuric acid.
denis23 [38]

Answer:

3.14 L of oxygen (O₂).

Explanation:

We'll begin by calculating the number of mole in 6.3 g of sulphur (S). This can be obtained as follow:

Molar mass of S = 32 g/mol

Mass of S = 6.3 g

Mole of S =.?

Mole = mass / molar mass

Mole of S = 6.3/32

Mole of S = 0.197 mole

Next, we shall write the overall equation of the reaction between sulphur (S) and oxygen (O₂) to produce sulphur trioxide (SO₃) .

This is illustrated below:

S (s) + O₂ (g) —> SO₂ (g)

SO₂ (g) + O₂ (g) —> 2SO₃ (s)

Overall reaction:

2S (s) + 3O₂ (g) —> 2SO₃ (g)

Next, we shall determine the number of mole of oxygen (O₂) needed to completely convert 6.30 g (i.e 0.197 mole) of sulfur.

This is illustrated below:

From the balanced equation above,

2 moles of sulphur (S) required 3 moles of oxygen (O₂) .

Therefore, 0.197 mole of sulphur (S) will require = (0.197 × 3)/2 = 0.296 mole of oxygen (O₂).

Therefore, 0.296 mole of oxygen (O₂) is needed.

Finally, we shall determine the volume of oxygen (O₂) needed as follow:

Number of mole (n) of oxygen (O₂) = 0.296 mole

Temperature (T) = 340 °С = 340 °С + 273 = 613 K

Pressure (P) = 4.75 atm

Gas constant (R) = 0.0821 atm.L/Kmol

Volume (V) of oxygen (O₂) =.?

PV = nRT

4.75 × V = 0.296 × 0.0821 × 613

Divide both side by 4.75

V = (0.296 × 0.0821 × 613) / 4.75

V = 3.14 L

Therefore, 3.14 L of oxygen (O₂) is needed for the reaction.

5 0
3 years ago
PLZ HELP ASAP
Verizon [17]

Answer:

Using glucose to provide energy for the body

Explanation:

3 0
3 years ago
Consider 4.00 L of a gas at 365 mmHg and 20. ∘C . If the container is compressed to 2.80 L and the temperature is increased to 3
stealth61 [152]

This is an exercise in<u> the General Combined Gas Law</u>.

To start solving this exercise, we obtain the following data:

<h3>Data:</h3>
  • V₁ = 4.00 l
  • P₁ = 365 mmHg
  • T₁ = 20 °C + 273 = 293 K
  • V₂ = 2,80 l
  • T₂ = 30 °C + 273 = 303 K
  • P₂ = ¿?

We apply the following formula:

  • P₁V₁T₂=P₂V₂T₁     ⇒  General formula

Where:

  • P₁=Initial pressure
  • V₁=Initial volume
  • T₂=end temperature
  • P₂=end pressure
  • T₂=end temperature
  • V₁=Initial temperature

We clear for final pressure (P2)

\large\displaystyle\text{$\begin{gathered}\sf P_{2}=\frac{P_{1}V_{1}T_{2}}{V_{2}T_{1}} \ \ \to \ \ \ Formula \end{gathered}$}

We substitute our data into the formula:

\large\displaystyle\text{$\begin{gathered}\sf P_{2}=\frac{(365 \ mmHg)(4.00 \not{l})(303 \not{K})}{(2.80 \not{l})(293\not{K})}  \end{gathered}$}

\large\displaystyle\text{$\begin{gathered}\sf P_{2}=\frac{442380 \ mmHg}{ 820.4 }  \end{gathered}$}

\boxed{\large\displaystyle\text{$\begin{gathered}\sf P_{2}=539.224 \ mmHg \end{gathered}$}}

Answer: The new canister pressure is 539.224 mmHg.

<h2>{ Pisces04 }</h2>
6 0
2 years ago
Balance the equation pls
mihalych1998 [28]

Answer:

copy and paste this equation into the website

Explanation:

https://en.intl.chemicalaid.com/tools/equationbalancer.php

4 0
3 years ago
A musk ox and the Alstroemeria flower have physical structures and organs that have similar functions. Provide two examples of s
iragen [17]

Answer: poop

Explanation:

its comes out of but

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3 years ago
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