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Ira Lisetskai [31]
3 years ago
10

The relationship between a cathode and an anode involves

Physics
1 answer:
astra-53 [7]3 years ago
5 0
It involves electrons.

The cathode is the electrode where electron deficient ions move to.

While the anode is electrode where electron excess ions move to.

So the relationship between Cathode and Anode involves electrons.

C.
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Which of the following describe advantages of using radio waves over other electromagnetic waves to transmit information to Eart
Whitepunk [10]

The correct options are:

D

"Radio waves have a lower frequency, which makes them safer for humans."

B

"Radio waves take less energy to produce."

<h3>Why do we radio waves over other electromagnetic waves to transmit information to Earth? </h3>

Radio waves are electromagnetic waves with frequencies on the range from 10 KHz to 10 THz.

Now, remember that all electromagnetic waves have the same speed, which is the speed of light, and the energy of a wave is proportional to its frequency.

Particularly, we can see that radio waves have small frequencies (smaller than infrared light) so these waves carry very little energy.

With that in mind, the correct options are.

D

"Radio waves have a lower frequency, which makes them safer for humans."

B

"Radio waves take less energy to produce."

These are the two main reasons of why we use radio waves.

If you want to learn more about electromagnetic waves.

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4 0
2 years ago
What's the name of the compound Kl?
Nat2105 [25]

Answer: Potassium iodide

Explanation: their you go

3 0
2 years ago
Read 2 more answers
Fraternity hazing is acceptable because it is an initational rite to the brotherhood
Fantom [35]

Answer:

that is the right answer

Explanation:

8 0
3 years ago
A vacuum cleaner produces sound with a measured sound level of 75.0 dB. (a) What is the intensity of this sound in W/m2? W/m2 (b
jonny [76]

Answer:

Part a)

I = 3.16 \times 10^{-5} W/m^2

Part b)

P_o = 0.162 Pa

Explanation:

Part a)

Level of sound = 75 dB

now we know that

L = 10 Log\frac{I}{I_0}

here we know that

I_0 = 10^{-12} W/m^2

now we have

75 = 10 Log(\frac{I}{10^{-12}})

I = 3.16 \times 10^{-5} W/m^2

Part b)

Intensity of sound wave is given as

I = \frac{1}{2}\rho A^2\omega^2 c

here we know that

A = \frac{P_o}{Bk}

so we have

I = \frac{1}{2}\rho(\frac{P_o}{Bk})^2\omega^2 c

I = \frac{1}{2}\rho P_o^2 \frac{c^3}{B^2}

now we know

\rho = 1.2 kg/m^3

c = 340 m/s

B = 1.4 \times 10^5 Pa

now we have

3.16 \times 10^{-5} = \frac{1}{2}(1.2)P_o^2\frac{340^3}{(1.4\times 10^5)^2}

P_o = 0.162 Pa

5 0
3 years ago
A charged atom is called a(n) _____.
katrin2010 [14]
A charged atom is called a(n) ion. It can be negative charge or positive.
3 0
3 years ago
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