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3 years ago

The relationship between a cathode and an anode involves

1 answer:

5 0

It involves electrons.

The cathode is the electrode where electron deficient ions move to.

While the anode is electrode where electron excess ions move to.

So the relationship between Cathode and Anode involves electrons.

C.

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You are given a sample of metal and asked to determine its specific heat. You weight the sample and find that its weight is 28.4

lidiya [134]

Answer:

The samples specific heat is 14.8 J/kg.K

Explanation:

Given that,

Weight = 28.4 N

Suppose, heat energy $E=1.25\times10^{4}\ J$

Temperature = 18°C

We need to calculate the samples specific heat

Using formula of specific heat

$Q=mc\Delta T$

$c=\dfrac{Q}{m\Delta T}$

Where, m = mass

c = specific heat

$\Delta T$ = temperature

Q = heat

Put the value into the formula

$c=\dfrac{1.25\times10^{4}}{\dfrac{28.4}{9.8}\times(18+273)}$

$c=14.8\ J/kg. K$

Hence, The samples specific heat is 14.8 J/kg.K

8 0

3 years ago

PLZ HELP!!!!

FrozenT [24]

I would think the answer is c.

5 0

3 years ago

Read 2 more answers

A myopic person (assume no astigmatism) is diagnosed with a far point of 160 cm. What corrective prescription should they be sup

Kazeer [188]

Answer:

The person should use a convex lens of power -0.625 D.

Explanation:

Given that, the far point of the person, with myopic eye, is 160 cm.

It means that the image of an object, which is at infinity, is formed at this point 160 cm distance away from the person's eye.

If the object is infinity, then the object distance, u = - $\infty$ .

Image distance, v = -160 cm.

u and v are taken to be negative because the object and the image of the object are on the side of the eye from where the light is coming.

Let the focal length of the lens which is to be used for the correction of this myopic eye be f, then using lens equation,

$\rm \dfrac 1f = \dfrac 1v-\dfrac 1u=\dfrac 1{-160 }-\dfrac1{-\infty}=\dfrac 1{-160}-0=\dfrac 1{-160}.\\\Rightarrow f=-160\ cm.$

The negative focal length indicates that the lens should be convex.

The power of the lens is given by

$\rm P=\dfrac{1}{f}=\dfrac{1}{-160\ cm }=\dfrac{1}{-1.6\ m}=-0.625\ D.$

So, the person should use a convex lens of power -0.625 D.

8 0

4 years ago

Read 2 more answers

What does a map scale 1:25,000 mean

Sav [38]

Every unit on the map equals 25000 of the unit in real life.

4 0

4 years ago

Two blocks (m1 40 kg, m2 30 kg) are connected by a compressed spring, and are initially at rest. The spring breaks and the two o

Snezhnost [94]

To develop this problem it is necessary to apply the equations related to the conservation of the moment, for which it is necessary that the velocities and the mass in an initial state must be equal to the mass and the velocity at the end point. Mathematically this can be described as

$m_1u_1+m_2u_2 = m_1v_1+m_2v_2$

$m_1$ = Mass of object 1

$m_2$ = Mass of the object 2

$u_{1,2}$ = Initital velocity of object 1 and 2

$v_{1,2}$ = Final velocity of object 1 and 2

Our values are given as,

$m_1 = 40kg$

$m_2 = 30kg$

There is not initial velocity, i.e, they are initially at rest.

We have the final velocity of the first object

$v_1 = 15m/s$

Replacing we have:

$m_1u_1+m_2u_2 = m_1v_1+m_2v_2$

$40*0+40*0=40*15+30*(v_2)$

$v_2=-20 m/s$

Therefore, the speed of the second block will be -20m / s or 20m / s if our vector reference system becomes positive for that direction. The correct answer is C.

5 0

3 years ago