Best way that I study is first get in a comfortable room. Get the material you are suppose to be studying and a blank note book. Go through what you think you know then take what you struggle with a write it in the notebook. After writing it a few times different ways find what helps you rember it the most.
Answer:
a) The voltage on resistor R1 is less than before. Letter B.
b) The current through R1 is less than before. Letter B.
c) The resistance of the circuit went up by adding R2 in series. Letter A.
Explanation:
a) The new resistor R2 was added in series, that means the same current goes through both resistors (R1 and R2) and that the sum of the individual voltage drop of those resistors should be the same as the voltage of the source. Before there was only resistor R1 connected to the source, so all the voltage of the source was being delivered to that component, but now it is divided between R1 and R2. So the voltage on R1 is less than previously. Letter B.
b) A battery works as a voltage source, so assuming it's charged, it delivers a value of voltage to the circuit, while the current flow through it is defined by the equivalent resistance across the terminals. Since the new resistor was added in series the total resistance of the circuit went up and the current delivered by the battery went down. Letter B.
c) Since the equivalent resistance for a series connection is the sum of the resistors, R12 = R1 + R2, the resistence went up. Letter A.
Answer:
Explanation:
Power P = .5 mW = .5 x 10⁻³
P = Emax² / 2μo x c , c is velocity of light , μo is permeability of air .
Emax² = P x 2μo x c
= .5 x 10⁻³ x 2 x 4π x 10⁻⁷ x 3 x 10⁸
= 37.68 x 10⁻²
Emax = 6.14 x 10⁻¹
= .614 v/m
b) Bmax = Emax / c
= .614 / 3 x 10⁸
= .2046 x 10⁻⁸ T
= 20.46 x 10⁻¹⁰ T.
B. A safe landing on the station on earth
hope this helps :D
