Answer:
y = 10.44cos(2t - 0.291) cm
Explanation:
y = Acos(2πt/T + φ) = Acos(2πt/π + φ) = Acos(2t + φ)
v = y' = -2Αsin(2t + φ)
10 = Acos(2(0) + φ) = Acosφ
6 = -2Αsin(2(0) + φ) = -2Asinφ
6/10 = -2Asinφ/Acosφ = -2tanφ
tanφ = -0.3
φ = -0.291 radians
10 = Acos(-0.291)
A = 10/cos(-0.291) = 10.44
Answer: 1
Explanation: The highest eccentricity an ellipse can have is '1', a straight line.
According to the current, the charge is 818.18 coulombs.
We need to know about current to solve this problem. Current can be defined as the flow rate of charge through the medium. It can be determined as
I = Q / t
where I is current, Q is charge and t is time.
From the question above, we know that
P = 25 W
V = 110 V
h = 1 hour = 3600 second
Calculate the current
P = V . I
25 = 110 . I
I = 0.23 A
By substituting the given parameters, we can calculate the charge
I = Q / t
0.23 = Q / 3600
Q = 818.18 coulombs
Hence, the charge is 818.18 coulombs.
Find more on current at: brainly.com/question/24858512
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Answer: the amount of mass is oscillating is 34.8 kg
Explanation:
Given that;
amplitude A = 20.0 cm
time t = 10 s
amplitude decreases x = 15.0 cm
damping coefficient b = 2.00 N.s/m
amount of mass is oscillating = ?
we know that; amplitude can be expressed as;
x = Ae^-(∝t)
we substitute
15 = 20e^-∝(10)
∝ = 0.02877 s⁻¹
Hence mass m will be;
m = b/2∝
we substitute
m = (2 N.s/m) / ( 2 × 0.02877 s⁻¹)
m = 34.8 kg
Therefore the amount of mass is oscillating is 34.8 kg
