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melomori [17]
3 years ago
13

Two closed containers look the same but when is packed with LED and the other with a few feathers how could you determine which

has more mass if you end the containers were orbiting in a weightless condition in outer space
Physics
2 answers:
Elanso [62]3 years ago
5 0
The lead has more mass because it is denser however the weights are equal in outer space
Rudik [331]3 years ago
3 0
You would want to push both containers, first one and then the other,
with exactly the same strength of push. 

The one that takes off slower (with less acceleration from the same
net force) is the one with more mass.
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Give the 7 color harmonies​
notsponge [240]

Answer:

Complementary colors.

Split complementary colors.

Analogous colors.

Triadic harmonies.

Tetradic harmonies.

Monochromatic harmonies.

Explanation:

7 0
2 years ago
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How to calculate sound of an echo ​
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by an echo meter

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2 years ago
A rubber balloon is filled with 1 L of air at 1 atm and 300 K and is then put into a cryogenic refrigerator at 100 K. The rubber
Kipish [7]

Answer:

The correct answers are

(a) It decreases to 1/3 L

(ii) is (c) It is constant

Explanation:

to solve this, we list out the number of knowns and unknowns so as to determine the correct equation to solve the problem

The given variables are as follows

Initial volume V1 = 1L

V2 = Unknown

Initial Temperature T1 = 300K

let us assume that the balloon is perfectly elastic

At 300K the balloon is filled and it stretches to maintain 1 atmosphere

at 100K the content of the balloon cools reducing the excitement of the gas content which also reduces the pressure, however, the balloon being perfectly elastic, contracts to maintain the 1 atmospheric pressure, hence the answer to (ii) is (c) It is constant,

For (i) since we know that the pressure of the balloon is constant

by Charles Law V1/T1 =V2/T2

or V2 = (V1/T1)×T2 =\frac{1L}{300K}× 100K= \frac{1}{3} × L = L/3 hence the correct answer to (i) is 1/3L

8 0
3 years ago
If pressure is increased from 200 kPa to 300 kPa, and the original volume of gas was 1.5 L, what is the new volume? Assume the t
Oxana [17]

Answer:

The answer to your question is:      V2 = 1 l

Explanation:

Data

P1 = 200 kPa

P2 = 300 kPa

V1 = 1.5 l

V2 = ?

Formula

                          P1V1 = P2V2

                          V2 = (P1V1) / P2

                          V2 = (200 x 1.5) / 300

                          V2 = 1 l

6 0
3 years ago
Astar is 10 light years away from the earth. Suppose it brightens up suddenly today, after how long can we see this change?
Blababa [14]

The phrase "light year" is a <u><em>distance</em></u> ... it's the distance that light travels through vacuum in one year.

When you look at an object located 1 light year away from you, you see it as it was 1 year ago.

If a star located 10 light years away from us suddenly brightens, or dims, or explodes, we see the event <em>10 years later.</em>

7 0
3 years ago
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