Answer:
161.86 N
Explanation:
mass of box m= 55.0 kg
weight of the box, mg= 55×9.81
g here is acceleration due to gravity =9.81 m/sec^2
coefficient of friction between the box and the surface μ= 0.3
the friction force F_s= μmg= 0.3×55×9.81
=161.86 N
to move the ball horizontal force required is 161.86 N
Answer:
7/150
Explanation:
The following data were obtained from the question:
Object distance (u) = 75cm
Image distance (v) = 3.5cm
Magnification (M) =..?
Magnification is simply defined as:
Magnification (M) = Image distance (v)/ object distance (u)
M = v /u
With the above formula, we can obtain the magnification of the image as follow:
M = v/u
M = 3.5/75
M = 7/150
Therefore, the magnification of the image is 7/150.
Answer:
The magnitude of F₁ is 3.7 times of F₂
Explanation:
Given that,
Time = 10 sec
Speed = 3.0 km/h
Speed of second tugboat = 11 km/h
We need to calculate the speed


The force F₁is constant acceleration is also a constant.

We need to calculate the acceleration
Using formula of acceleration



Similarly,

For total force,


The speed of second tugboat is


We need to calculate total acceleration



We need to calculate the acceleration a₂



We need to calculate the factor of F₁ and F₂
Dividing force F₁ by F₂



Hence, The magnitude of F₁ is 3.7 times of F₂
Answer:
4/3
Explanation:
Shown in the picture attached
Answer:
velocity changes over time.