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Pachacha [2.7K]
3 years ago
13

An air-standard otto cycle has compression ratio 10 and maximum cycle temperature 1000 k. evaluate the thermal efficiency and sp

ecific work of the cycle. what would be the thermal efficiency and specific work if it was a diesel cycle to the same maximum temperature? what would be the thermal efficiency and specific work if it was a dual pressure cycle to the same maximum temperature, where half the energy addition was from constant volume and half the energy addition as from constant pressure?
Physics
1 answer:
Tasya [4]3 years ago
7 0
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Astronaut mark uri is space-traveling from planet x to planet y at a speed of relative to the planets, which are at rest relativ
lyudmila [28]
<span>From the point of view of the astronaut, he travels between planets with a speed of 0.6c. His distance between the planets is less than the other bodies around him and so by applying Lorentz factor, we have 2*</span>√1-0.6² = 1.6 light hours. On the other hand, from the point of view of the other bodies, time for them is slower. For the bodies, they have to wait for about 1/0.6 = 1.67 light hours while for him it is 1/(0.8) = 1.25 light hours. The remaining distance for the astronaut would be 1.67 - 1.25 = 0.42 light hours. And then, light travels in all frames and so the astronaut will see that the flash from the second planet after 0.42 light hours and from the 1.25 light hours is, 1.25 - 0.42 = 0.83 light hours or 49.8 minutes.
5 0
3 years ago
An organ system is best described by which of the following?
earnstyle [38]
A group of cells together
3 0
3 years ago
Read 2 more answers
Martin has severe myopia, with a far point on only 17 cm. He wants to get glasses that he'll wear while using his computer whose
marusya05 [52]

Answer:

Explanation:

Far point = 17 cm . That means he can not see beyond this distance .

He wants to see at an object at 65 cm away . That means object placed at 65 has image at 17 cm by concave lens . Using lens formula

1 / v - 1 / u = 1 / f

1 / - 17 - 1 / - 65 = 1 / f

= 1 / 65 - 1 / 17

= -  .0434 = 1 / f

power = - 100 / f

= - 100 x .0434

= - 4.34 D .

6 0
4 years ago
a 28.7 KG sled is pulled forward with a 63 net force across the ground with MK equals 0.169 what is the acceleration of the sled
abruzzese [7]

Answer:

0.54\ \text{m/s}^2

Explanation:

F = Force on the sled = 63 N

m = Mass of sled = 28.7 kg

\mu_k = Coefficient of kinetic friction = 0.169

g = Acceleration due to gravity = 9.81\ \text{m/s}^2

The force balance of the system is given by

F-\mu_k mg=ma\\\Rightarrow a=\dfrac{F-\mu_k mg}{m}\\\Rightarrow a=\dfrac{63-0.169\times 28.7\times 9.81}{28.7}\\\Rightarrow a=0.54\ \text{m/s}^2

The acceleration of the sled is 0.54\ \text{m/s}^2.

5 0
3 years ago
What are 3 types of frictions and when does each apply/9029244/29edc63f?utm_source=registration
Anon25 [30]
- Static friction: when an object is not moving
- Kinetic friction: if an object is moving
- Rolling friction: when there is rolling (wheel,..)
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3 years ago
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