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Leni [432]
3 years ago
8

While flying due east at 33 m/s, an airplane is also being carried due north at 12 m/s by the wind. What is the plane's resultan

t velocity?
Physics
2 answers:
zaharov [31]3 years ago
8 0

Answer:35.11

Explanation:

kodGreya [7K]3 years ago
4 0

Answer:

21m/s east is the resultant velocity

Explanation:

I got this answer as 33 - 12 = 21

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Please Help!!!! I WILL GIVE BRAINLIEST!!!!!!!!!!!!!
Bas_tet [7]

Given info

d = 0.000250 meters = distance between slits

L = 302 cm = 0.302 meters = distance from slits to screen

\theta_8 = 1.12^{\circ} = angle to 8th max (note how m = 8 since we're comparing this to the form \theta_m)

x_n = x_5 = 3.33 \text{ cm} = 0.0333 \text{ meters} (n = 5 as we're dealing with the 5th minimum )

---------------

Method 1

d\sin(\theta_m) = m\lambda\\\\0.000250\sin(\theta_8) = 8\lambda\\\\8\lambda = 0.000250\sin(1.12^{\circ})\\\\\lambda = \frac{0.000250\sin(1.12^{\circ})}{8}\\\\\lambda \approx 0.000 000 61082633\\\\\lambda \approx 6.1082633 \times 10^{-7} \text{meters}\\\\ \lambda \approx 6.11 \times 10^{-7} \text{ meters}\\\\ \lambda \approx 611 \text{ nm}

Make sure your calculator is in degree mode.

-----------------

Method 2

\Delta x = \frac{\lambda*L*m}{d}\\\\L*\tan(\theta_m) = \frac{\lambda*L*m}{d}\\\\\tan(\theta_m) = \frac{\lambda*m}{d}\\\\\tan(\theta_8) = \frac{\lambda*8}{0.000250}\\\\\tan(1.12^{\circ}) = \frac{\lambda*8}{0.000250}\\\\\lambda = \frac{1}{8}*0.000250*\tan(1.12^{\circ})\\\\\lambda \approx 0.00000061094306 \text{ meters}\\\\\lambda \approx 6.1094306 \times 10^{-7} \text{ meters}\\\\\lambda \approx 611 \text{ nm}\\\\

-----------------

Method 3

\frac{d*x_n}{L} = \left(n-\frac{1}{2}\right)\lambda\\\\\frac{0.000250*3.33}{302.0} = \left(5-\frac{1}{2}\right)\lambda\\\\0.00000275662251 \approx \frac{9}{2}\lambda\\\\\frac{9}{2}\lambda \approx 0.00000275662251\\\\\lambda \approx \frac{2}{9}*0.00000275662251\\\\\lambda \approx 0.00000061258279 \text{ meters}\\\\\lambda \approx 6.1258279 \times 10^{-7} \text{ meters}\\\\\lambda \approx 6.13 \times 10^{-7} \text{ meters}\\\\\lambda \approx 613 \text{ nm}\\\\

There is a slight discrepancy (the first two results were 611 nm while this is roughly 613 nm) which could be a result of rounding error, but I'm not entirely sure.

7 0
3 years ago
Why must one use a reference point to determine whether or not an object is in motion
GaryK [48]
Because there's no such thing as "really" moving. 
ALL motion is always relative to something.

Here's an example:
You're sitting in a comfy cushy seat, reading a book and listening
to your .mp3 player, and you're getting drowsy.  It's so warm and
comfortable, your eyes are getting so heavy, finally the book slips
out of your hand, falls into your lap, and you are fast asleep.

-- Relative to you, the book is not moving at all.
-- Relative to the seat, you are not moving at all.
-- Relative to the wall and the window, the seat is not moving at all.
-- But your seat is in a passenger airliner.  Relative to people on the
    ground, you are moving past them at almost 500 miles per hour !
-- Relative to the center of the Earth, the people on the ground are moving
   in a circle at more than 700 miles per hour.  
-- Relative to the center of the Sun, the Earth and everything on it are moving
   in a circle at about 66,700 miles per hour ! 

How fast are they REALLY moving ?
There's no such thing.
It all depends on what reference you're using.

7 0
3 years ago
Discuss velocity by providing at least one example and explain why velocity is either a scalar or vector quantity.
grandymaker [24]
Velocity is speed plus direction, so an example of velocity would be a vehicle traveling at 75mph north. Velocity is a vector quantity because it describes both magnitude and direction.
5 0
3 years ago
Read 2 more answers
Work is a transfer of (1 point) energy. force. mass. motion.
jok3333 [9.3K]
Energy is the ability to do work.

So work can not be done without the transfer of energy from one body to another.

Work is the transfer of energy.
6 0
3 years ago
Read 2 more answers
A
asambeis [7]

Answer:

22Volts

Explanation:

The pd at the terminal is known as the emf

Since there are Ten 2.2V cells

Terminal voltage = number of cells * pd of one cell

Terminal voltage = 10 * 2.2

Terminal voltage = 22V

Hence the pd at the battery terminals​ is 22Volts

4 0
3 years ago
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