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olya-2409 [2.1K]
4 years ago
12

The local news team is tracking the storm and has reported that it is traveling north, northwest at 20 miles per hour. The repor

ter has told us the storm's
Physics
2 answers:
Fantom [35]4 years ago
6 0

Answer:

Velocity of storm

Explanation:

As we know that all vectors are defined by their magnitude and direction both. Here as we can see that the reporter told about the flow speed of air which is 20 miles per hour. Also the reporter mentioned the direction in which this air is blowing.

velocity = \frac{displacement}{time}

So here we can find the magnitude of air flow as well as we can also find the direction of air flow.

So here this represents the vector quantity which is known as velocity.

So here we will say that the storm velocity is reported by the reporter here in the given statement

NeX [460]4 years ago
5 0
The correct answer is velocity

Velocity includes speed, time, and direction, making it a vector unit. Velocity shows at what speed something is moving for how long in what direction, which is what happens here.

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Answer:

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Explanation:

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3 years ago
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What do we call an instrument that makes things look large?
skelet666 [1.2K]
Is it a magnifying glass?
8 0
3 years ago
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A potential difference of 1.20 V will be applied to a 33.0 m length of 18-gauge copper wire (diameter = 0.0400 in.). Calculate (
Nostrana [21]

Answer:A) Current = 1.739A, B)current density, J = 2.147x10^6 A/m2

magnitude of electric field , E =  0.036 N/C

)rate of thermal energy, P  =2.086W

Explanation:

Resistance  = R =   ρL/A

But the cross-section area of the wire. is given as

Diameter / 2 = 0.04/2 =0.02in to m = 0.02 / 39.37= 0.000508

A = πr^2 = π x  0.000508^2 = 8.10 x 10^-7

since resistivity of copper,ρ= 17x10-9 ohm.m

so resistance is   R =   ρL/A

17x10-9  x 33 / 8.1x10-7

= 0.69 ohm.

A) Current =    I = Voltage /Resistance =1.20/0.69 =1.739A

B)current density, J = Current /Area

= 1.739/8.1x10-7

= 2.147x10^6 A/m2

c)magnitude of electric field , E =  Current density x resistivity =J ρ

E = 2.147 x 10^6  x 17  x 10^-9

E = 0.036 N/C

D)rate of thermal energy, P  = I² R =1.739² X 0.69

=2.086W

6 0
3 years ago
Astronomers discover an exoplanet, a planet obriting a star other than the Sun, that has an orbital period of 3.27 Earth years i
Naddik [55]

Answer:

  r = 3.787 10¹¹ m

Explanation:

We can solve this exercise using Newton's second law, where force is the force of universal attraction and centripetal acceleration

    F = ma

    G m M / r² = m a

The centripetal acceleration is given by

    a = v² / r

For the case of an orbit the speed circulates (velocity module is constant), let's use the relationship

    v = d / t

The distance traveled Esla orbits, in a circle the distance is

    d = 2 π r

Time in time to complete the orbit, called period

     v = 2π r / T

Let's replace

    G m M / r² = m a

    G M / r² = (2π r / T)² / r

    G M / r² = 4π² r / T²

    G M T² = 4π² r3

     r = ∛ (G M T² / 4π²)

Let's reduce the magnitudes to the SI system

     T = 3.27 and (365 d / 1 y) (24 h / 1 day) (3600s / 1h)

     T = 1.03 10⁸ s

Let's calculate

      r = ∛[6.67 10⁻¹¹ 3.03 10³⁰ (1.03 10⁸) 2) / 4π²2]

      r = ∛ (21.44 10³⁵ / 39.478)

      r = ∛(0.0543087 10 36)

      r = 0.3787 10¹² m

      r = 3.787 10¹¹ m

7 0
3 years ago
Its important please answer ​
Yuri [45]

Answer: Well we see that v= u- ft/m

lets say that ft= feet and m= mass

so you divide those and subtract u

leaving you with the value of v which is 13

7 0
3 years ago
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