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Brrunno [24]
3 years ago
12

A cyclist pedals his bike and reaches the top of a hill. Then he begins to coast downhill without pedaling. When he reaches the

bottom of the hill, he again applies force to the pedals. Why does the cyclist accelerate as he coasts downhill? A. The force of friction propels the cyclist and the bicycle down the hill. B. The mass of the cyclist opposes the mass of the bicycle, causing it to accelerate downhill. C. The unbalanced force of gravity acts on the mass of his body and the bicycle. D. The force of the cyclist and the force of the bicycle added together increase the downhill acceleration.
Physics
2 answers:
balu736 [363]3 years ago
6 0
I would say the answer is D: The force of the cyclist and the force of the bicycle add together increasing downhill acceleration.

Hope this helps
Fantom [35]3 years ago
5 0
The correct answer is d


yay
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How did the social structure of ancient Rome affect the lives of its people?
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Explanation:

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In which of these samples do the molecules most likely have the most kinetic energy? (2 points)
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A jogger travels a route that has two parts. The first is a displacement of 3 km due south, and the second involves a displaceme
spayn [35]

Answer:

a) 2.41 km

b) 38.8°

Questions c and d are illegible.

Explanation:

We can express the displacements as vectors with origin on the point he started (0, 0).

When he traveled south he moved to (-3, 0).

When he moved east he moved to (-3, x)

The magnitude of the total displacement is found with Pythagoras theorem:

d^2 = dx^2 + dy^2

Rearranging:

dy^2 = d^2 - dx^2

dy = \sqrt{d^2 - dx^2}

dy = \sqrt{3.85^2 - 3^2}  = 2.41 km

The angle of the displacement vector is:

cos(a) = dx/d

a = arccos(dx/d)

a = arccos(3/3.85) = 38.8°

7 0
3 years ago
What must be the acceleration of a train in order for it to stop 12 m/s in a distance if 541 m
earnstyle [38]

Answer:

The acceleration of the train must be - 0.133 m/s²

Explanation:

Lets explain how to solve the problem

A train in order for it to stop 12 m/s in a distance if 541 m

That means the initial velocity of the train is 12 m/s

Its final velocity is zero (stop)

The distance it covers is 541 m

We want to find its acceleration

The acceleration will be negative quantity because the train reduced its

velocity from 12 m/s to zero

We need rule contains velocity, acceleration and distance

So we will use ⇒<em> v² = u² + 2as</em>, where v is the final velocity, u is the

initial velocity, a is the acceleration and s is the distance

v = 0, u = 12 m/s, s = 541 m

Substitute these values in the rule

(0)² = (12)² + 2(a)(541)

0 = 144 + 1082 a

Subtract 144 from both sides

-144 = 1082 a

Divide both sides by 1082

- 0.133 = a

<em>The acceleration of the train must be - 0.133 m/s²</em>

3 0
3 years ago
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