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olya-2409 [2.1K]
3 years ago
13

According to the phase diagram for H20 what happens to the phases of water at 1 atm pressure as the temperature is increased fro

m -10 degrees Celsius to 110 degrees

Chemistry
2 answers:
Alex787 [66]3 years ago
6 0
D because the solid evaporates
asambeis [7]3 years ago
4 0

Answer:

B

Explanation:

follow the chart starting at the y axis go away from it at the level of 1 till you hit 100

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leva [86]

Explanation: energy levels are three(counting number of cyecles) outer electrons are 3 also

Answer:3,3

6 0
3 years ago
All of the following are benefits of recycling except?
IgorLugansk [536]
Recycling Isn’t Always Cost Effective.
High Up Front Cost
Needs More Global Buy-In.
Recycled Products Are Often of Lesser Quality.
Recycling Sites Are Commonly Unsafe.
6 0
3 years ago
What moves the pieces of salt on top of the speaker when the music is playing
Ksivusya [100]

Answer:

the friction?? or the movement

Explanation:

sense the salt is so light its easy to move

5 0
3 years ago
Explain how particles move before during and after melting
Aleksandr-060686 [28]

Answer:

Particles would move more freely, while still staying close together depending on the shape of the liquid

Explanation:

Melting is the process of going from a solid to a liquid due to the increase in heat/energy. This increase in heat/energy increases the speed at which the atoms within the object moves. Lets say we had an ice cube. While it is a cube, the particles inside the cube are slow and compact, staying close together.

When enough energy is gained, this makes the particles begin to move faster, gaining heat and energy which results in the ice cube melting and moving more freely than normal.

3 0
2 years ago
Read 2 more answers
Titration of a 20.0-mL sample of acid rain required 1.7 mL of 0.0811 M NaOH to reach the end point. If we assume that the acidit
Rasek [7]

Answer:

Concentration of sulfuric acid in the acid rain sample is 0.0034467 mol/L.

Explanation:

Volume of NaOH = 1.7 ml = 0.0017 L

Molarity of NaOH = 0.0811 M

Moles of NaOH = n

0.0811 M=\frac{n}{0.0017 L}

n = 0.0001378 mol

H_2SO_4+2NaOH\rightarrow Na_2SO_4+2H_2O

According to reaction, 2 mol of NaOH neutralize 1 mol of sulfuric acid.

Then 0.0001378 mol of NaOH will neutralize:

\frac{1}{2}\times 0.0001378 mol=6.8935\times 10^{-5} mol of sulfuric acid.

Concentration of sulfuric acid in the acid rain sample: x

x=\frac{6.8935\times 10^{-5}}{0.02 L}=0.0034467 mol/L

Concentration of sulfuric acid in the acid rain sample is 0.0034467 mol/L.

7 0
3 years ago
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