The molarity of the acid sample H₂SO₄ is 0.052M .
<h3>What is Molarity ?</h3>
Molarity (M) is the amount of a substance in a certain volume of solution.
Molarity is defined as the moles of a solute per liters of a solution.
Molarity is also known as the molar concentration of a solution
Now to determine the molarity of the acid sample
V( H₂SO₄) = 24.0 mL in liters = 24.0 / 1000 = 0.024 L
M(H₂SO₄) = ?
V(NaOH) = 20.0 mL = 20.0 / 1000 = 0.02 L
M(NaOH) = 0.125 M
Number of moles NaOH :
n = M x V
n = 0.125 x 0.02
n = 0.0025 moles of NaOH
H₂SO₄(aq) + 2 NaOH(aq) = Na₂SO₄(aq) + 2 H₂O(l)
1 mole H₂SO₄ ---------- 2 mole NaOH
? mole H₂SO₄ ---------- 0.0025 moles NaOH
moles = 0.0025 * 1 / 2
= 0.00125 moles of H₂SO₄
M(H₂SO₄) = n / V
M = 0.00125 / 0.024
= 0.052 M
Therefore the molarity of the acid sample H₂SO₄ is 0.052M .
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Answer:
The snow absorbed radiant energy to produce a physical change.
Explanation:
Answer : The value of equilibrium constant for this reaction at 328.0 K is
Explanation :
As we know that,
where,
= standard Gibbs free energy = ?
= standard enthalpy = 151.2 kJ = 151200 J
= standard entropy = 169.4 J/K
T = temperature of reaction = 328.0 K
Now put all the given values in the above formula, we get:
The relation between the equilibrium constant and standard Gibbs free energy is:
where,
= standard Gibbs free energy = 95636.8 J
R = gas constant = 8.314 J/K.mol
T = temperature = 328.0 K
K = equilibrium constant = ?
Now put all the given values in the above formula, we get:
Therefore, the value of equilibrium constant for this reaction at 328.0 K is
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Explanation: the ratio will never change no matter the air pressure!
Answer:
it is the only one going up
Explanation: