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Lady bird [3.3K]
3 years ago
9

Which of these is a compound? carbon dioxide potassium salt water salad

Chemistry
2 answers:
Snowcat [4.5K]3 years ago
5 0
Pretty sure it’s potassium
xz_007 [3.2K]3 years ago
5 0
salt water because it’s Salt + water
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The volume of a cube is calculated by using the following formula: l x h x w. The length (l), height (h), and width (w) of a met
aliya0001 [1]

Answer:

8.909466637830

Explanation:

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8 0
2 years ago
What mass of HBO2 is produced from the<br> combustion of 139.5 g of B2H6?<br> Answer in units of g.
aliina [53]

Answer:

m_{HBO_2}=441.8gHBO_2

Explanation:

Hello there!

In this case, since the combustion of B2H6 is:

B_2H_6+3O_2\rightarrow 2HBO_2+2H_2O

Thus, since there is 1:2 mole ratio between the reactant and product, the produced grams of the latter is:

m_{HBO_2}=139.5gB_2H_6*\frac{1molB_2H_6}{27.67gB_2H_6} *\frac{2molHBO_2}{1molB_2H_6} *\frac{43.82gHBO_2}{1molHBO_2}

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Best regards!

5 0
2 years ago
0.58 mol of Mg contains how many atoms? please show work
Jet001 [13]

The number of atoms present in 0.58 mole of magnesium, Mg is 3.49×10²³ atoms

<h3>Avogadro's hypothesis </h3>

1 mole of Mg = 6.02×10²³ atoms

<h3>How to determine the atoms in 0.58 mole of Mg </h3>

1 mole of Mg = 6.02×10²³ atoms

Therefore,

0.58 mole of Mg = 0.58 × 6.02×10²³

0.58 mole of Mg = 3.49×10²³ atoms

Thus, 3.49×10²³ atoms are present in 0.58 mole of Mg

Learn more about Avogadro's number:

brainly.com/question/26141731

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3 0
2 years ago
What is the critical temperature at which hydrogen can begin to fuse into helium in the core?
Black_prince [1.1K]
Negative 0 hope this helps
4 0
3 years ago
A solution at 25 degrees Celsius has a pH of 4.48. What is the pOH of this solution?
just olya [345]

Hello :)

I just took the quiz, so let me give you a step-by-step explanation of how I solved the problem. Disregard the 25 degrees, it is not needed to find the answer

pH + pOH = 14

4.48 (4.48 is the given pH in problem) + pOH = 14

4.48-4.48 + pOH = 14-4.48 (subtract 4.48 from 14)

pOH = 9.52 (letter c)

Hope this helped :)

4 0
3 years ago
Read 2 more answers
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