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3 years ago

what is the mean and mad of 33,78,99,87,90,67 plz answer this fast you will be the brainliest person

Mathematics

1 answer:

Bas_tet [7]3 years ago

3 0

Answer:

The mean and mad of this is 75.67(rounded to nearest hundredth) and 17.10 because the deviations are: 42.6, 2.33, 23.33, 11.33, 14.33, 8.67.

Step-by-step explanation:

You might be interested in

2 2/3 of what number is 6 1/7

borishaifa [10]

$2\frac{2}{3}$ of $2\frac{17}{56}$ is $6\frac{1}{7}$

Solution:

Given $2\frac{2}{3}$ of what number is $6\frac{1}{7}$ .

Let us first convert the mixed fraction into improper fraction.

$$2\frac{2}{3}=\frac{(2\times3)+2}{3}=\frac{8}{3}$

$$6\frac{1}{7}=\frac{(6\times7)+1}{3}=\frac{43}{3}$

Now, let us take the unknown number be x.

$$2\frac{2}{3}\times x=6\frac{1}{7}$

$$\frac{8}{3}\times x=\frac{43}{7}$

Do the cross multiplication.

$$ x=\frac{43}{7}\times\frac{3}{8}$

$$ x=\frac{43\times3}{7\times8}$

$$ x=\frac{129}{56}$

Now, again change the improper fraction into mixed fraction.

$$ x=2\frac{17}{56}$

Hence $2\frac{2}{3}$ of $2\frac{17}{56}$ is $6\frac{1}{7}$ .

6 0

4 years ago

(2x+4)^2 - (x-5)^2 = 26x Please solve (explained)

Zina [86]

Expand the squared binomials:

$(2x+4)^2=4x^2+16x+16$

$(x-5)^2=x^2-10x+25$

Then

$(4x^2+16x+16)-(x^2-10x+25)=3x^2+26x-9=26x$

$\implies3x^2-9=0$

$\implies3x^2=9$

$\implies x^2=3$

$\implies x=\pm\sqrt3$

5 0

3 years ago

In how many ways can a

Tomtit [17]

Answer:

The answer is 364. There are 364 ways of choosing a recorder, a facilitator and a questioner froma club containing 14 members.

This is a Combination problem.

Combination is a branch of mathematics that deals with the problem relating to the number of iterations which allows one to select a sample of elements which we can term "r" from a collection or a group of distinct objects which we can name "n". The rules here are that replacements are not allowed and sample elements may be chosen in any order.

Step-by-step explanation:

Step I

The formula is given as

$C (n,r) = \frac{n}{r} = \frac{n!}{(r!(n-r)!)}$

n (objects) = 14

r (sample) = 3

Step 2 - Insert Figures

C (14, 3) = $(\frac{14}{3})$ = $\frac{14!}{(3!(14-3)!)}$

= $\frac{87178291200}{(6 X 39916800)}$

= $\frac{87178291200}{239500800}$

= 364

Step 3

The total number of ways a recorder, a facilitator and a questioner can be chosen in a club containing 14 members therefore is 364.

Cheers!

6 0

3 years ago

You and a friend are driving go-karts on two different tracks. As you drive on a straight section heading east, your friend pass

yKpoI14uk [10]

No they cross each other like a highway. You are on the underpass and your friend passes over you. As in, they are crossing a bridge & you are below them.

5 0

3 years ago

Solve each system by elimination. 1) 10x + 7y=9 -4x - 7y=9

stellarik [79]

Answer:

(3, -3)

Step-by-step explanation:

When asked to solve by elimination, you put them on top of one another, like you're going to add it.

10x + 7y = 9

-4x - 7y = 9

See that 7y? You can cancel those out because one is negative, and one is positive. So those are gone. You finish adding the rest of the numbers as usual and solve for x.

6x = 18

x = 3

Take x, and plug it into either equation to find y.

10(3) + 7y = 9

7y = -21

y = -3

(3, -3)

Hope this helped!

8 0

3 years ago