Answer:
- Partial pressure He = 276 torr
- Partial pressure Ar = 457 torr
- Total pressure = 733 torr
Explanation:
Assuming temperature remains constant, we can use Boyle's law to solve this problem: P₁V₁=P₂V₂.
Once the two flasks are connected and the stopock opened, the total volume is:
Now we use Boyle's law <em>twice</em>, to <u>calculate the new pressure of </u><em><u>each</u></em><u> gas</u>:
- He ⇒ 752 torr * 275 mL = P₂He * 750 mL
P₂He = 276 torr
- Ar ⇒ 722 torr * 475 mL = P₂Ar * 750 mL
P₂Ar = 457 torr
Finally we <u>calculate the total pressure</u>, adding the partial pressures:
- Total pressure = P₂He + P₂Ar = 733 torr
The answer is 11.0231131%, i hope this helped if it did please help me.
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Answer:
5118.50 J
Explanation:
pΔv=nRΔT ;
therefore, ΔT=PV/nR
ΔT = (6.4×10^5)(3.2×10^(-3)/1×8.314
ΔT= 2.4633×10^2 = 246.33 K
specific heat at constant pressure is given as:
c_p = 3/2R
c_p = 12.5 J/mol K
Now, substitute in equation (1)
we know that
Q=ΔU+W ;
and
W=pΔV= 6.4×10^5×3.2×10^(-3) = 2048 J
now
ΔU=CvΔT = 12.465×246.33 =3070.50 J ;
therefore
Q=3070.50+2048= 5118.50 J