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sergeinik [125]
3 years ago
8

Which activity best demonstrates Ernest Rutherford’s creativity?

Chemistry
1 answer:
LenaWriter [7]3 years ago
4 0

with his well-known gold foil experiment in which he demonstrated that the atom has a tiny and heavy nucleus.

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Identify the functional groups present in each molecule.
Colt1911 [192]

Answer:

Carbon 3 is double bonded to an oxygen and attached to carbon 2 and carbon 4. :

Answer: Carbonyl group ( Ketone or aldehyde)

Carbon 17 is attached to an oxygen, which is attached to a hydrogen. :

Answer: Carboxyl group (Carboxylic acid)

A central carbon is attached to an amine, two hydrogens, and a carbon that is double bonded to an oxygen and single bonded to an oxygen attached to a hydrogen. :

Answer: Amide group

An amide group contains both amine and carboxyl

.

5 0
3 years ago
Charles’ Law can be expressed mathematically as V=kT. If the constant k for 6.0 L of gas is 0.020 L/K (liters per kelvin), what
kozerog [31]

Answer: 300 K

Explanation:

Charles' Law: This law states that volume is directly proportional to the temperature of the gas at constant pressure and number of moles.

V\propto T    (At constant pressure and number of moles)

V=kT

Given : V= 6.0 L

k= 0.020 L/K

T=?

6.0=0.020LK^{-1}\times T

T=300 K

Thus temperature of the gas is 300 K.

3 0
3 years ago
HELP ME ON NUMBER 8 ASAP
Varvara68 [4.7K]

Answer:

2. hope it helps. please follow me I'm new here

3 0
3 years ago
Hexane and heptane are miscible with each other in all proportions. In making a solution of them, is the entropy of the system i
Damm [24]

Answer: Option (a) is the correct answer.

Explanation:

A miscible solution is defined as the one in which two or more than two components are soluble with each other.

So, when hexane is added to heptane then both of them will mix with each other and hence they are miscible. This mixing will lead to formation of more number of ions into the solution as a result, more will be the disorder present in the solution.

As entropy is the degree of randomness present.

Hence, we can conclude that a solution of hexane and heptane will lead to an increase in entropy.

8 0
3 years ago
A stock solution of sodium sulfate NaSO4 has a concentrate of 1.00 m. The volume of this solution is 50 ml. What volume of 0.25
mylen [45]
<h3>Answer:</h3>

200 mL

<h3>Explanation:</h3>

Concept tested: Dilution formula

We are given;

  • Concentration of stock solution as 1.00 M
  • Volume of the stock solution as 50 mL
  • Molarity of the dilute solution as 0.25 M

We are required to calculate the volume of diluted solution;

  • The stock solution is the original solution before dilution while diluted solution is the solution after dilution.
  • Using the dilution formula we can determine the volume of diluted solution;

M1V1 = M2V2

Rearranging the formula;

V2 = M1V1 ÷ M2

     = (1.00 M × 50 mL) ÷ 0.25 M

     = 200 mL

Therefore, a volume of 200mL of 0.25 M solution could be made from the stock solution.

5 0
3 years ago
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