His measurements are precise since his pH values are close to each other in a way that it was repeated in all measurements. On the contrary to accuracy, it is the closeness to the actual pH value he should have achieved. Therefore, Jose's results are precise but not accurate since his value is not close to the actual value of pH 4.
Answer:
The new volume of the balloon is 38.5 L
Explanation:
Step 1: Data given
Volume at the start = V1 = 35.0 L
Temperature at the start = T1 = 303 Kelvin
Volume by 3pm = TO BE DETERMINED
Temperature by 3pm = 333 Kelvin
<u>Step 2: </u>Calculate the new volume
Charles' gas law says
V1/T1 = V2/T2
V
1 is the initial volume and T1 is the initial temperature
V2 is the final volume and T2 is the final temperature
35 L / 303 Kelvin = V2 / 333 Kelvin
V2 = 35L * 333 Kelvin / 303 Kelvin
V2 = 38.47L ≈ 38.5 L
The new volume of the balloon is 38.5 L
Answer:
1 (348) (D2) = 273 (2.05) (0.805) D2= 1.29 g/L
Explanation:
Ok to answer this question we firsst need to fin the number of mol of Urea (CH4N2O). to do this we simply :
1 mol of urea =15/60.055 = 0.25mol
therefore 200g of water contain 0.25mol
the next step is to determine the malality of our solution in 200g of water, to do this we say:
200 g = 1Kg/1000g = 0.2kg
therefor 0.25mol/0.2Kg = 1.25mol/kg
and from the equation:
we know that i = 1
we are given Kf
b is the molality that we just calculated
therefore;
the solutions freezing point is -2.325°C
Answer:
Original temperature (T1) = - 37.16°C
Explanation:
Given:
Gas pressure (P1) = 2.75 bar
Temperature (T2) = - 20°C
Gas pressure (P2) = 1.48 bar
Find:
Original temperature (T1)
Computation:
Using Gay-Lussac's Law
⇒ P1 / T1 = P2 / T2
⇒ 2.75 / T1 = 1.48 / (-20)
⇒ T1 = (2.75)(-20) / 1.48
⇒ T1 = -55 / 1.48
⇒ T1 = - 37.16°C
Original temperature (T1) = - 37.16°C
