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Lapatulllka [165]
4 years ago
9

During normal operation, an electrical component experiences a constant rate of ohmic dissipation ini g = 0.01 W that causes the

conversion of electrical to thermal energy. The component has conductivity k = 10 W/m-K, density r = 1000 kg/m3 , and specific heat capacity c = 100 J/kg-K. The surface of the component is cooled by convection with air at T[infinity] = 20ºC and heat transfer coefficient h = 10 W/m2 -K. The volume of the component is V = 1x10-7 m3 and its surface area is As = 1x10-5 m2.
a. Is a lumped capacitance model of the component appropriate? Justify your answer
b. Assume that your answer to (a) is yes. What is the steady-state temperature of the 0m component?
c. Assume that your answer to (a) is yes. What is the lumped capacitance time constant of the component? At time t - 0, the power to the circuit is shut off and the ohmic dissipation in the component decays to zero according to where τ 6-25 s is the electrical time constant of the circuit.
d. Sketch the temperature of the component as a function of time after the circuit is shut off Be sure to indicate where the temperature starts, where it ends up, and approximately how long it takes to get there.
e. Derive the ordinary differential equation for this problem.
f. What is the initial condition for this problem?

Engineering
1 answer:
Llana [10]4 years ago
4 0

Answer:

Check the explanation

Explanation:

Kindly check the attached image below for the step by step explanation to your answer.

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zimovet [89]

Answer:

The power spectral density of Y(t) is Syy(w) = \frac{32}{(4+w^2)(16+w^2)}

Explanation:

4 0
4 years ago
What is 100 kPa in psia?
Korolek [52]

Answer:

The pressure in pounds per square inch (psi) equals 14.50 psi.

Explanation:

Since psi stands for 'pounds per square inch' and Pascals stands for 'Newtons per square meters'

We can write the given pressure as

Pressure=100kPa\\\\Pressure=100\times 10^{3}N/m^{2}

Now since 1 Newton of force equals 0.22481 Pound force also

since 1 meter equals 39.37 inches

Using the above values we get

Pressure=100\times 10^{3}\times \frac{0.22481lb}{(39.37)^{2}inch^{2}}

thus the pressure becomes

Pressure=100\times 10^{3}\times \frac{0.22481}{(39.31)^{2}}pounds/inch^{2}\\\\Pressure=14.50psi

8 0
3 years ago
The hoist of a crane consists of a 10 kW electric motor running at 1440 rpm drivine 300 mm diameter drunn through a 60:1 gear re
MissTica

Answer:

 Load =  2.42 tons

Lifting speed = 24 RPM

Explanation:

Given that

Power=10 KW

Efficiency = 90%

So the actual power,P=0.9 x 10 =9 KW

Speed of motor = 1440 RPM

Diameter of drum = 300 mm

radius =150 mm

G=60:1

Lets take speed of drum =N

We know that

G=\dfrac{Speed\ of\ motor}{Speed\ of\ drum}

60=\dfrac{1440}{N}

N=24 RPM

We know that

P=\dfrac{2\pi NT}{60}

Where T is the torque

9000=\dfrac{2\pi \times 24\times T}{60}

T=3580.98 N.m

Lets take load =F

So T= F x r

3580.98 = F x 0.15

F=23.87 KN

We know that

1 KN=0.109 tons

So 23.87 KN= 2.42 tons

So the load =  2.42 tons

Lifting speed = 24 RPM

8 0
3 years ago
For a refrigerator, COP<1 a) True b) False
WINSTONCH [101]

Answer:

False

Explanation:

COP is Coeficient of performance, it relates useful heat moved with work consumed, it is used in refrigerators and heat pumps.

For refrigerators the useful heat is the one extracted from the cold reservoir. Therefore:

COP = \frac{Tcold}{T.hot - Tcold}

This often exceeds 1.

4 0
3 years ago
What are the laws that apply to one vehicle towing another?
Sergeu [11.5K]
The drawbar or other connections must be strong enough to pull all the weight of the vehicle being towed. The drawbar or other connection may not exceed 15 feet from one vehicle to the other.
5 0
3 years ago
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