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Lapatulllka [165]
3 years ago
9

During normal operation, an electrical component experiences a constant rate of ohmic dissipation ini g = 0.01 W that causes the

conversion of electrical to thermal energy. The component has conductivity k = 10 W/m-K, density r = 1000 kg/m3 , and specific heat capacity c = 100 J/kg-K. The surface of the component is cooled by convection with air at T[infinity] = 20ºC and heat transfer coefficient h = 10 W/m2 -K. The volume of the component is V = 1x10-7 m3 and its surface area is As = 1x10-5 m2.
a. Is a lumped capacitance model of the component appropriate? Justify your answer
b. Assume that your answer to (a) is yes. What is the steady-state temperature of the 0m component?
c. Assume that your answer to (a) is yes. What is the lumped capacitance time constant of the component? At time t - 0, the power to the circuit is shut off and the ohmic dissipation in the component decays to zero according to where τ 6-25 s is the electrical time constant of the circuit.
d. Sketch the temperature of the component as a function of time after the circuit is shut off Be sure to indicate where the temperature starts, where it ends up, and approximately how long it takes to get there.
e. Derive the ordinary differential equation for this problem.
f. What is the initial condition for this problem?

Engineering
1 answer:
Llana [10]3 years ago
4 0

Answer:

Check the explanation

Explanation:

Kindly check the attached image below for the step by step explanation to your answer.

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An insulated piston-cylinder device contains 5 L of saturated liquid water at a constant pressure of 175 kPa. Water is stirred b
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The three sub regions of South America are the Andes Mountains, the Amazon Rainforest, and the Eastern Highlands. The Atacama De
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A pipe produces successive harmonics at 300 Hz and 350 Hz. Calculate the length of the pipe and state whether it is closed at on
MAXImum [283]

Answer:

The pipe is open ended and the length of pipe is 3.4 m.

Explanation:

For identification of the type of pipe checking the successive frequencies in both the open pipe and closed pipe as below

Equation for nth frequency for open end pipe is given as

f_n=\frac{nv}{2L}

For (n+1)th value the frequency is

f_{n+1}=\frac{(n+1)v}{2L}

Taking a ratio of both equation and solving for n such that the value of n is a whole number

\frac{f_{n+1}}{f_n}=\frac{\frac{(n+1)v}{2L}}{\frac{nv}{2L}}\\\frac{350}{300}=\frac{(n+1)}{n}\\350n =300n+300\\50n =300\\n =6\\

So n is a whole number this means that the pipe is open ended.

For confirmation the  nth frequency for a closed ended pipe is given as

f_n=\frac{(2n+1)v}{4L}

For (n+1)th value the frequency is

f_{n+1}=\frac{(2n+3)v}{4L}

Taking a ratio of both equation and solving for n such that the value of n is a whole number

\frac{f_{n+1}}{f_n}=\frac{\frac{(2n+3)v}{2L}}{\frac{(2n+1)v}{2L}}\\\frac{350}{300}=\frac{(2n+3)}{(2n+1)}\\700n+350 =600n+900\\100n =550\\n =5.5\\

As n is not a whole number so this is further confirmed that the pipe is open ended.

Now from the equation of, with n=6, v=340 m/s and f=300 Hz

f_n=\frac{nv}{2L}\\300=\frac{6 \times 340}{2L}\\L=\frac{2040}{600}\\L=3.4 m

The value of length is 3.4m.

5 0
3 years ago
Question 1: Final Results = What are the values of the resistances such that the gain = -100, Rin = 1 MI2. Don't use resistances
lidiya [134]

Answer:

Explanation:

In a study of algebra, you will encounter many families of equations, or groups of

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more advanced families. In addition to solving linear equations, we’ll use the skills we

develop to solve for a specified variable in a formula, a practice widely used in science,

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A. Solving Linear Equations Using Properties of Equality

An equation is a statement that two expressions are

equal. From the expressions and

we can form the equation

which is a linear equation in one variable. To solve

an equation, we attempt to find a specific input or xvalue that will make the equation true, meaning the

left-hand expression will be equal to the right. Using

Table 1.1, we find that is a

true equation when x is replaced by 2, and is a false

equation otherwise. Replacement values that make

the equation true are called solutions or roots of the equation.

4 0
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