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sashaice [31]
3 years ago
14

I WILL GIVE BRAINLIEST

Physics
1 answer:
Sveta_85 [38]3 years ago
4 0
A. Air, desk, water. sound travels the slowest through air and the fastest through liquids. solids are somewhere in the middle.
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A sound wave travelling in water has a frequency of 100 Hz. The speed of sound in water is 1482 m/s. Calculate the wavelength of
xz_007 [3.2K]
Steps : The formula for wavelength is:
λ = v/f
λ = 1482/100

Answer:

λ = 14.82 m
6 0
2 years ago
Which of the following is evidence that supports the idea of uniformitarianism?
Inga [223]
D. rates of soil erosion are much lower during droughts that last several years
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4 years ago
A 2 kg rubber ball is thrown at a wall horizontally at 3 m/s, and bounces back the way it came at an equal speed. A 2 kg clay ba
Lyrx [107]

Answer:

THE RUBBER BALL

Explanation:

From the question we are told that

      The mass of the rubber ball is m_r   =  2 \ kg

      The  initial  speed of the rubber ball is  u =  3 \ m/s

      The final speed at which it bounces bank v  - 3 \ m/s

      The mass of the clay ball  is  m_c =  2  \ kg

       The  initial  speed of the clay  ball is u = 3 \ m/s

       The final speed of the clay ball is  v = 0 \  m/s

Generally Impulse is mathematically represented as

       I  =  \Delta p

where \Delta  p is the change in the linear momentum so  

       I  =  m(v-u)

For the rubber  is  

        I_r  =  2(-3 -3)

       I_r  = -12\ kg \cdot  m/s

=>     |I_r|  = 12\ kg \cdot  m/s

For the clay ball

       I_c  =  2(0-3)

        I_c =  -6 \ kg\cdot \ m/s

=>    | I_c| =  6 \ kg\cdot \ m/s

So from the above calculation the ball with the a higher magnitude of impulse is the rubber ball

       

8 0
4 years ago
What power of an engine is required to pump 2450N of water per second from a well 50m deep to the surface
Arisa [49]
The correct one is A
4 0
3 years ago
A kettle of water contains 1.2 kg of water. Calculate how much energy is required to hear it from water at 10 degrees to its boi
Darya [45]

Answer:

450 kJ

Explanation:

Q = mCΔT

where Q is heat (energy),

m is mass,

C is specific heat capacity,

and ΔT is the temperature change.

Q = (1.2 kg) (4180 J/kg/°C) (100°C − 10°C)

Q = 451,440 J

Q ≈ 450 kJ

6 0
3 years ago
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