The density of Liquid T is less than that of water.
So, Liquid T will float on water.
<h3>Answer:</h3>
D. Liquid T
well, you divide 4 by 5, so .8
.8 of a mile is 4224 feet.
i really hope this helps :)
The particle with sharp ends have the slowest rate of deposition
Answer: Option C
<u>Explanation:</u>
As per aerosol physics, deposition is a process where aerosol particles accumulate or settle on solid surfaces. Thereby, it reduces the concentration of particles in the air. Deposition velocity (rate of deposition) defines from F = vc, where v is deposition rate, F denotes flux density and c refers concentration.
Deposition velocity is slowest for particles of intermediate-sized particles because the frictional force offers resistance to the flow. Density is directly proportional to the deposition rate so clearly shows that high-density particles settle faster. Due to friction, round and large-sized particles deposit faster than oval/flattened sediments.
So, the force of gravity that the asteroid and the planet have on each other approximately 
<h3>Introduction</h3>
Hi ! Now, I will help to discuss about the gravitational force between two objects. The force of gravity is not affected by the radius of an object, but radius between two object. Moreover, if the object is a planet, the radius of the planet is only to calculate the "gravitational acceleration" on the planet itself,does not determine the gravitational force between the two planets. For the gravitational force between two objects, it can be calculated using the following formula :

With the following condition :
- F = gravitational force (N)
- G = gravity constant ≈
N.m²/kg²
= mass of the first object (kg)
= mass of the second object (kg)- r = distance between two objects (m)
<h3>Problem Solving</h3>
We know that :
- G = gravity constant ≈
N.m²/kg²
= mass of the planet X =
kg.
= mass of the planet Y =
kg.- r = distance between two objects =
m.
What was asked :
- F = gravitational force = ... N
Step by step :





<h3>Conclusion</h3>
So, the force of gravity that the asteroid and the planet have on each other approximately

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