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soldier1979 [14.2K]
3 years ago
11

What is missing from the temperature and volume graph shown at right?

Chemistry
2 answers:
olga55 [171]3 years ago
8 0
Through looking at the graph, i feel that its the number of the temperature.
pochemuha3 years ago
8 0

Answer: The vertical axis should labelled as 'Volume (unit)' as it is missing from the given graph.

Explanation:

The labeling of vertical axis is missing from the given graph between the temperature and volume.

The vertical axis should labelled as 'Volume (unit)'  because it is given that the graph is in between the temperature and the volume.And temperature is on the horizontal axis is already labeled in the graph.

On top of the graph name of the graph should also be written as Temperature vs Volume graph.

From the unit we mean that the unit in which is used in measuring the volume and in the graph like: L ,mL etc.

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Calculate the number of moles of Cl2 produced at equilibrium when 3.98 mol of PCl5 is heated at 283.9 deg celsius in a vessel ha
ddd [48]

Answer:

1.274 moles

Explanation:

The equation for the reaction can be represented as follows:

                       PCl_5(g)           ⇄       PCl_3(g)     +         Cl_2(g)

K = 0.060

K = \frac{[PCl_3][Cl_2]}{[PCl_5]}

Concentration of   PCl_5(g)  = \frac{numbers of moles}{volume}

Concentration of   PCl_5(g)  = \frac{3.98}{10.0}

Concentration of   PCl_5(g)  = 0.398 moles

If we construct an ICE table for the above equation; we have:

                       PCl_5(g)           ⇄       PCl_3(g)     +         Cl_2(g)

Initial                0.398                          0                          0

Change            - x                               + x                        + x

Equilibrium    (0.398 - x)                      x                          x

K = \frac{[PCl_3][Cl_2]}{[PCl_5]}

K = \frac{[x][x]}{[0.398-x]}

K = \frac{x^2}{0.398-x}

0.060 = \frac{x^2}{0.398-x}

0.06(0.398-x) = x²

0.02388 - 0.060x = x²

x² + 0.060x - 0.02388 = 0               (quadratic equation)

a = 1;       b= 0.06;      c= -0.02388

Using quadratic formula;

=  \frac{-b+/-\sqrt{b^2-4ac} }{2a}

= \frac{-0.06+/-\sqrt{(0.06)^2-4(1)(-0.02388)} }{(2*1)}

= \frac{-0.060+/-\sqrt{0.0036+0.09552} }{2}

= \frac{-0.06+/-\sqrt{0.09912} }{2}

= \frac{-0.06+/-0.3148}{2}

= \frac{-0.060+0.3148}{2}   or \frac{-0.060-0.3148}{2}

= \frac{0.2548}{2}  or \frac{-0.3748}{2}

= 0.1274 or -0.1874

We go by the positive value which says:

[x] = 0.1274 M

number of moles = 0.1274 × 10.0

= 1.274 moles

∴ the number of moles  of Cl₂ produced at equilibrium = 1.274 moles

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Answer:

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<u>2.37</u> is the pH of 0.075 M HZ.

<h3>What is pH?</h3>

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The pH scale is inversely indicates to the concentration of hydrogen ions in the solution and is logarithmic.

⇒pH = -log(a_{H+})

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