A 60 kg skydiver is falling at a terminal velocity of 50 m/s.
1 answer:
Answer:
The gravitational force is definitely acting downwards towards the ground and this is equal to the weight of the skydiver.
the acceleration a = 7.8 m/s²
Explanation:
Given that :
the mass of the skydiver = 60 kg
Velocity = 50 m/s
Thus; gravitational force is definitely acting downwards towards the ground and this is equal to the weight of the skydiver.
Also; the air resistance is acting upward and the resultant of both forces = mass×acceleration
So;
mg-R = ma
60(9.8) - 120 = 60(a)
588 -120 = 60a
468 = 60a
a =
a = 7.8 m/s²
Hence, the acceleration a = 7.8 m/s²
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162.78 m/s is the most probable speed of a helium atom.
Explanation:
The most probable speed:
= Boltzmann’s constant =
T = temperature of the gas
m = mass of the gas particle.
Given, m =
T = 6.4 K
Substituting all the given values :
162.78 m/s is the most probable speed of a helium atom.
Answer:
t = 5.48 × 10⁻³ s
Explanation:
Given:
ΔV = ΔVmax × sin(2πft)
frequency, f = 16.9Hz
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ΔV = ΔVmax × sin(2π×16.9×ft)
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i = V/R
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i = current
V = voltage
hence,
also, given at time 't' the current in the circuit is 55.0% of the peak current
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t = 5.48 × 10⁻³ s (Answer)