Question

A chemist mixes 71.1 g of carbon tetrachloride with 65.4 g of isopropenylbenzene and 4.02 g of 2-ethyltoluene. Calculate the percent by mass of each component of this solution. Be sure each of your answer entries has the correct number of significant digits mass percentー1 □ component 0% carbon tetrachloride isopropenylbenzene 2-ethyltoluene

Answer 1

Answer:

%  Carbon tetrachloride = 50.6 %

% isopropenylbenzene = 46.5 %

% 2-ethyltoluene = 2.9%

Explanation:

Step 1: Data given

A mixture contains:

71.1 grams of Carbon tetrachloride (CCl4)

65.4 grams of isopropenylbenzene (C9H10)

4.02 grams of 2-ethyltoluene (C9H12)

Step 2: Calculate total mass

Total mass = mass CCl4 + mass C9H10 + mass C9H12

Totam mass = 71.1g + 65.4g + 4.02g

Total mass = 140.52 grams

Step 3: Calculate % of each component:

% component = (mass component/ total mass) *100%

%  Carbon tetrachloride = (71.1 / 140.52) *100 %

%  Carbon tetrachloride = 50.6 %

% isopropenylbenzene = (65.4 / 140.52) *100%

% isopropenylbenzene = 46.5 %

% 2-ethyltoluene = (4.02/140.52) *100%

% 2-ethyltoluene = 2.9%

50.6% + 46.5% + 2.9% = 100%

Answer 2

Answer:

∴ wt% CCl4 = 50.597 %

∴ wt% C9H10 = 46.541 %

∴ wt% C9H12 = 2.861 %

Explanation:

• wt% = ((mass solute)/(mass solution))×100

⇒ mass sln = 71.1 g CCl4 + 65.4 C9H10 + 4.02 g C9H12

⇒ mass sln = 140.52 g

∴ CCl4:

⇒ wt% CCl4 = ((71.1 g CCl4)/(140.82 g sln))×100

⇒ wt% CCl4 = 50.597 %

∴ C9H10:

⇒ wt% C9H10 = ((65.4 g C9H10)/(140.52 g sln))×100

⇒ wt% C9H10 = 46.541 %

∴ C9H12:

⇒ wt% C9H12 = ((4.02 g C9H12)/(140.52 g sln))×100

⇒ wt% C9H12 = 2.861 %