Explanation:
<h3>
Need to FinD :</h3>
- The velocity of the ball with strikes the ground.
- The time of the ball after which it strikes the ground.
We know that,
- The ball is dropped from the height of 30 m as stated in the question. Therefore, it will have a initial velocity of 0 m/s. The distance travelled by the ball will be 30 metres as the distance travelled by the ball is equal to the height of the tower and that is 30 metres.
So, by using the third equation of motion, we will find out the final velocity of the ball.
Therefore,
∴ Hence, the required final velocity of the ball with which it strikes the ground is 24.5 m/s. Since, we know that the initial velocity of the ball is 0 m/s and the acceleration of the ball is 10 m/s². So, by using the first equation of motion, we will find out the time of the ball after which it stikes the ground.
Therefore,
∴ Hence, the required time of the ball after which it strikes the ground is 2.45 seconds.
If we have I= 7.5 A:
I think my solution might just help you answer the problem on your own:
You have the formulas correct, watch your signs and BRACKETS.
B = μ0/(2π) (Current) / (Perpendicular distance)
Since μ0=4π E -7 Tm/A, we have:
B1 = (4πE-7 Tm/A)(7.5 A)/[2π (0.030 m)] = 5E-5 T
B2 = (4πE-7 Tm/A)(-7.5 A)/[2π (0.150 m)] = -1E-1 T
So BA = B1 + B2 = ?
(It looks like you just left out the square brackets, hence multiplying Pi and 0.03 and 0.15 instead of dividing them.)
<span>For the point B, the two distances are -0.060 m and +0.060 m. Be careful with the signs. Unlike point A, the two components will have the same sign.</span>
Answer:
I think is 3 I am not sure
Helllo fellow brainly student!
The best answer is A- with a screen.
This is the best choice because
what this means is to use a sifter.
A sifter is a screen like tool you can
Use to make the lumps disappear from
Flour, sugar, and other cooking ingredients.
Hope this helps! Have a jolly evening.
Answer:
Answered
Explanation:
Damping by inert gas is directly proportional to the molecular mass of inert gas.
Damping by inert gas is inversely proportional to the specific heat. One should consider specific heat at constant volume here as pressure will be varying. Since molecular mass is constant, the height of peak will be reduced proportional to the molecular mass.
There is an increase in temperature during detonation of pressure.
Increase in temperature difference, decreases the specific heat and therefore increases the damping.