Answer:
a) 1.8 kJ
Explanation:
ΔG=-RtLnK
Just input the data into the equation to gives us the result, in Joules.
ΔG=-8.314*(25+273.15)*ln(0.48)
ΔG=1819,37 J
But there is only 2 significant figures, so we express it as or 1.8 kJ
The following statement about soil formation are true:
1. The composition of soil depend largely on the composition of the parent rock.
2. Strong roots of shrubs and trees hold on to soil and protect it from erosion.
3. Soil formed from local rock is residual soil and soil formed from distant rock is transported soil.
Soil are typically formed from rocks. The nature of the soil depend on the type of rock from which the soil was formed. It takes a long time for a soil to be formed from a parent rock. Erosion is the process that carries the surface soil away, but the root of shrub and trees usually prevent this by holding on to the soil particles.
Answer:
234.35 °C
Explanation:
Given data:
Volume of balloon = 125000 mL
Moles of oxygen = 3 mol
Pressure = 1 atm
Temperature = ?
Solution:
Formula:
PV = nRT
P = Pressure
V = volume
n = number of moles
R = ideal gas constant
T = temperature
Volume of balloon = 125000 mL × 1 L /1000 mL
Volume of balloon = 125 L
Now we will put the values:
Ideal gas constant = R = 0.0821 atm.L/mol.K
PV = nRT
T = PV/nR
T = 1 atm × 125 L/ 0.0821 atm.L/mol.K × 3 mol
T= 125 /0.2463 /K
T = 507.5 K
K to °C
507.5 K - 273.15 = 234.35 °C
Answer:
The mass of glycerol that the student should weigh out depends on the volume that is needed. For example, the density of glycerol is 1.26 g/mL. Then, if 500 mL of glycerol is needed, 630 g should be weighed.
Explanation:
Density is the amount of mass per unit of volume. Density relates how many grams 1 milliliter of a substance weighs. Thus, if the density of glycerol is 1.26 g/mL means that 1.26 grams of glycerol occupy 1 mL of volume, or, in other words, 1 mL of glycerol weighs 1.26 grams.
Therefore, if 500 mL of glycerol is required to use for an experiment, 630 grams need to be weighed:
1 mL glycerol________ 1.26 g
500 mL glycerol______ x= 500mL * 1.26 g / 1 mL = 630 g