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goblinko [34]
3 years ago
13

If the volume of two containers stays the same , and one containers temperature is lowered, what happens to the pressure in the

cooler container ?
Chemistry
1 answer:
melisa1 [442]3 years ago
5 0
Gay-Lussacs law states that pressure is directly proportional to temperature at constant volume.
in this case the volumes of the 2 containers remain the same therefore volume is constant.
P/ T = k
where P - pressure, T - temperature and k - constant 
when temperature decreases the pressure too decreases and vice versa.
if temperature of one container is lowered the pressure also reduces.
since one containers temperature is lowered the pressure in that container reduces. 

answer is when temperature is lowered, pressure too is lowered. 
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denpristay [2]
Hydrogen and oxygen! Happy holidays btw
3 0
3 years ago
Help me with these questions.
Aloiza [94]
1) C
2) B
3) A/B not sure
4) C I think

5 0
3 years ago
Balance the following equations. Do not include the states of matter.<br><br> (a) C + O2 → CO
krek1111 [17]

Answer:

C + O2 → CO2

Explanation:

C + O2 → CO ----------------- (1)

from equ (1) on reactant side, C has 1 mole, O has 2 moles

from equ (1) on product side, C has 1 mole, O has 1 mole

Thus, to balance the equation, O should have 2 moles

C + O2 → CO2

7 0
3 years ago
Read 2 more answers
A sample containing 2.30 mol of Ne gas has an initial volume of 8.00 L. What is the final volume, in liters, when the following
marta [7]

Answer:

a. 4,00L

b. 16,00L

c. 12,31L

Explanation:

Avogadro's law says:

\frac{V_1}{n_1} =\frac{V_2}{n_2}

a. If initial conditions are 2,30mol and 8,00L and you lose one-half of atoms, that means you have 1,15mol:

\frac{8,00L}{2,30mol} =\frac{V_2}{1,15mol}

<em>V₂ = 4,00L</em>

b. If initial conditions are 2,30mol and 8,00L and you add 2,30mol, that means you have 4,60mol:

\frac{8,00L}{2,30mol} =\frac{V_2}{4,60mol}

<em>V₂ = 16,00L</em>

c. 25,0g of Ne are:

25,0g × (1mol / 20,1797g) = 1,24 moles of Ne. That means you have 2,30mol - 1,24mol = 3,54mol of Ne

\frac{8,00L}{2,30mol} =\frac{V_2}{3,54mol}

<em>V₂ = 12,31L</em>

I hope it helps!

6 0
3 years ago
A steel block has a volume of 0.08 m³ and a density of 7,840 kg/m³. What is the force of gravity acting on the block (the weight
melomori [17]

Given:

volume of 0.08 m³

density of 7,840 kg/m³

Required:

force of gravity

Solution:

Find the mass using density equation.

D = M/V

M = DV

M = (7,840 kg/m³)(0.08 m³)

M = 627.2kg

 

F = Mg

F = (627.2kg)(9.8m/s2)

F = 6147N

7 0
3 years ago
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