3. alters the reaction mechanism.
Answer: (a) The solubility of CuCl in pure water is .
(b) The solubility of CuCl in 0.1 M NaCl is .
Explanation:
(a) Chemical equation for the given reaction in pure water is as follows.
Initial: 0 0
Change: +x +x
Equilibm: x x
And, equilibrium expression is as follows.
x =
Hence, the solubility of CuCl in pure water is .
(b) When NaCl is 0.1 M,
,
,
Net equation:
= 0.1044
So for,
Initial: 0.1 0
Change: -x +x
Equilibm: 0.1 - x x
Now, the equilibrium expression is as follows.
K' =
0.1044 =
x =
Therefore, the solubility of CuCl in 0.1 M NaCl is .
At the right angle. Both molecules have to be going fast enough and at the right angle or else they will just bounce off
The magnitude of the force causing this acceleration is 15 N
<u>Explanation:</u>
we know that
F=ma: According to the newton's second law
F - force acting on the object
m - mass of the object
a - acceleration
Newton's second law states that acceleration depends on force acting on the object and mass of the object.
Force is directly proportional to acceleration and mass is inversely proportional to acceleration.
here,
m = 5 kg
a = 3 m/s2
Answer:
9.606 grams of citric acid are present in 125 mL of a 0.400 M citric acid solution.
Explanation:
Molarity : It is defined as the number of moles of solute present in one liter of solution. Mathematically written as:
Moles of citric acid = n
Volume of the citric acid solution = 125 mL =125 × 0.001 L= 0.125 L
(1 mL = 0.001L)
Molarity of the citric acid solution = 0.400 M
n = 0.400 M × 0.125 L = 0.05 moles
Mass of 0.05 moles of citric acid :
9.606 grams of citric acid are present in 125 mL of a 0.400 M citric acid solution.