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3 years ago

What makes the Arrhenius acid and an Arrhenius base definition incomplete or lacking

Chemistry

1 answer:

Kryger [21]3 years ago

7 0

Answer:

See Explanation

Explanation:

The Arrhenius acid-base theory defines an acid as a compound which when added into water increases the hydronium ion (H₃O⁺) concentration and the base as a compound which when added into water increases the hydroxide (OH⁻) ion concentration. As such, an acid-base reaction is limited to proton transfer to only OH⁻ ions forming water. Such would imply that all acid-base reactions produce water only in addition to a salt. This is not always the case as conjugate base anions for many substances can receive proton transfer.

Example: The reaction HOAc + NaCN => HCN + OAc- will occur in aqueous media because the proton (H⁺) on acetic acid (HOAc) will transfer to the cyanate ion forming hydrocyanic acid (HCN). Such occurs because the CN⁻ ion is a stronger conjugate base than the acetate ion (OAc⁻) and forms the more stable weak acid. Such is the basis of the Bronsted-Lowry Acid-Base system and states that an acid (proton donor) will transfer its ionizable hydrogen to a conjugate base (proton acceptor) if the transfer forms a weaker acid.

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Choose from Blood tests vs Breath tests to answer the following questions about Blood

Solnce55 [7]

Answer:

Which type of BAC test is more accurate :- Blood

Which type of BAC test can be administered more quickly and is more portable :- Breath

Which type of BAC test is used more often in the field :- Breath

I hope it helps.

5 0

3 years ago

A compound is 2. 00% H by mass, 32. 7% S by mass, and 65. 3% O by mass. What is its empirical formula? The final step is to use

LekaFEV [45]

The empirical formula of this compound is $H_2SO_4$

Given the following data:

Percentage of H = 2.00%

Percentage of S = 32.7%

Percentage of O = 65.3%

Scientific data:

Molar mass of hydrogen (H) = 1.0 g/mol.

Molar mass of sulfur (S) = 32 g/mol.

Molar mass of oxygen (O) = 16 g/mol.

To determine the empirical formula of this compound:

Note: We would assume that the mass of the compound is 100 grams.

Hence, the mass of its constituent elements are:

Mass of hydrogen (H) = 2.00 grams

Mass of sulfur (S) = 32.7 grams

Mass of oxygen (O) = 65.3 grams

Next, we would determine the number of moles of each element by using this formula:

$Number\;of\;moles = \frac{mass}{molar\;mass}$

For hydrogen (H):

$Number\;of\;moles = \frac{2.00}{1}$

Number of moles = 2.0 moles

For sulfur (S):

$Number\;of\;moles = \frac{32.7}{32}$

Number of moles = 1.0 moles

For oxygen (O):

$Number\;of\;moles = \frac{65.3}{16}$

Number of moles = 4.0 moles

Empirical formula = $H_2SO_4$

3 0

2 years ago

ASAP

raketka [301]

Answer:

84%

Explanation:

2100 j out / 2500 j in = .84 = 84%

7 0

2 years ago

A beach has a supply of sand grains composed of calcite, ferromagnesian silicate minerals, and non-ferromagnesian silicate miner

bezimeni [28]

Ferromagnesian silicate minerals (i looked it up)

4 0

3 years ago

CdF2(s)⇄Cd2+(aq)+2F−(aq)A saturated aqueous solution of CdF2 is prepared. The equilibrium in the solution is represented above.

kupik [55]

Answer:

The correct answer is option a.

Explanation:

$CdF_2(s)\rightleftharpoons Cd^{2+}(aq)+2F^-(aq)$

Equilibrium concentration cadmium ions = $[Cd^{2+}]=0.0585 M$

Equilibrium concentration fluoride ions = $[F^{-}]=0.117 M$

Molar solubility is the maximum concentration of salt present in water in ionic form beyond that no more salt will exist in its ionic form and will settle down in bottom of the solution.

The molar solubility of the solid cadmium fluoride = 0.0585 M

$CdF_2(s)\rightleftharpoons Cd^{2+}(aq)+2F^-(aq)$ ..[1]

$NaF(s)\rightleftharpoons Na^{+}(aq)+F^-(aq)$

Due to addition of sodium fluoride will increase concentration of fluoride in the solution.And due to common ion effect the equilibrium will shift in backward direction in [1], that is precipitation of more cadmium fluoride.

Hence, decrease in solubility will be observed.

8 0

3 years ago