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Lesechka [4]
4 years ago
8

What is the symbol beryllium is most likely to form ? and what kind of ion is it ?

Chemistry
2 answers:
IgorC [24]4 years ago
8 0

<u>Answer:</u>

Ion is a charged particle.

A neutral atom contains equal number of positive protons and negative electrons

When an electron is lost or gained the atom becomes a charged particle which is called as an ION.

For example  

Na is an atom which contains 11 electrons and 11 protons (= to atomic number)

When Na loses an electron it will have 11 positive proton and 10 negative electron and Thus, Na will become Na^+, a charge particle which we call it as sodium ion.

Cl is an atom which contains 17 electrons and 17 protons (= to atomic number)

When Cl loses an electron it will have 17 positive proton and 18 negative electron and Thus, Cl will become Cl^-, a charge particle which we call it as chloride ion.

When an ion is positively charged it is called as a cation

When an ion is negatively charged it is called as an anion.

Beryllium forms Be^{+2} cation.we see this in Beryllium chloride BeCl_2.

If BeCl_2 is present in water it forms Beryllium ions which is in Hydrated form that is H_2 O molecules are present  in its ion [Be(H_2 O)_4 ]^{+2}.

zheka24 [161]4 years ago
7 0

Answer:

Explanation:

The symbol of beryllium is Be. It is located in the second group on the periodic table.

Beryllium is a divalent cation with a charge of +2.

It is capable of losing 2 electrons in order to be like the noble gas He and this is a more stable configuration.

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What is the partial pressure of helium gas in a mixture that contains 8.00 grams of helium and 8.60 mol argon gas with a total p
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P_{He}=9.06torr

Explanation:

Hello there!

In this case, we can identify the solution to this problem via the Dalton's rule because the partial pressure of helium is given by:

P_{He}=x_{He}P_T

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n_{He}=8.00g\frac{1mol}{4.00g}=2.00mol\\\\ x_{He}=\frac{n_{He}}{n_{He}+n_{Ar}} \\\\ x_{He}=\frac{2.00mol}{2.00mol+8.60mol}\\\\x_{He}=0.189

Then, we calculate the partial pressure as shown below:

P_{He}=0.189 *48.0torr\\\\P_{He}=9.06torr

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