Answer:
There are there are 8.13-10^25
Explanation:
N(CS2)= 1.35* (times) 6.02-10^ 25= 3.13-10^25 molecules
Answer:
The correct option is: AgNO₃(aq) + KCl(aq) = AgCl(s) + KNO₃(aq)
Explanation:
Precipitation reaction is a chemical reaction that involves reaction between <em>two soluble salts to give an insoluble salt.</em> This <u>insoluble salt exists as a solid</u> and settles down.
Therefore, the solid formed in a precipitation reaction is known as the precipitate.
As the solid silver nitrate (AgNO₃) and solid potassium chloride (KCl) are <u>soluble in water</u>, therefore, their aqueous solutions are represented as AgNO₃(aq) and KCl(aq), respectively.
The precipitation reaction of AgNO₃(aq) and KCl(aq) gives an <u>insoluble salt, silver chloride (AgCl) and a soluble salt, potassium nitrate (KNO₃).</u>
The insoluble salt, <u>AgCl is called the precipitate</u> and is represented as AgCl(s). Whereas, the <u>soluble salt</u>, KNO₃ is represented as KNO₃ (aq).
<u>Therefore, the chemical equation for this precipitation reaction is:</u>
AgNO₃(aq) + KCl(aq) → AgCl(s) + KNO₃(aq)
Answer:
A scientific theory is a well-substantiated explanation of some aspect of the natural world that is acquired through the scientific method and repeatedly tested and confirmed, preferably using a written, pre-defined, protocol of observations and experiments.
Explanation:please mark as brainlies
Answer:
Chemistry is a branch of science that involves the study of the composition, structure and properties of matter. Often known as the central science, it is a creative discipline chiefly concerned with atomic and molecular structure and its change, for instance through chemical reactions.Explanation:Chemistry is a branch of science that involves the study of the composition, structure and properties of matter. Often known as the central science, it is a creative discipline chiefly concerned with atomic and molecular structure and its change, for instance through chemical reactions.
Answer:
116 years
Explanation:
To solve this, we will use the half life equation;
A(t) = A_o(½)^(t/t_½)
Where;
A(t) is the amount of strontium left after t years;
A_o is the initial quantity of strontium that will undergo decay;
t_½ is the half-life of strontium
t is the time it will take to decay
We are given;
A(t) = 7.5 g
A_o = 120 g
From online values, half life of strontium-90 is 29 years. Thus, t_½ = 29
Thus;
7.5 = 120 × ½^(t/29)
Divide both sides by 120 to get;
7.5/120 = ½^(t/29)
0.0625 = ½^(t/29)
In 0.0625 = (t/29) In ½
-2.772589 = (t/29) × (-0.693147)
(t/29) = -2.772589/(-0.693147)
t/29 = 4
t = 29 × 4
t = 116 years
