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Contact [7]
3 years ago
8

How high the boiling point can be elevated depends on the

Chemistry
1 answer:
n200080 [17]3 years ago
7 0
<span>C) Density of the particles of solute in the solution</span>
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What are the two main factors that affect deep ocean currents​
Alex_Xolod [135]

Answer:

coastal and sea floor features influence their location direction and speed coriolis effect also influence deep ocean current

5 0
3 years ago
When 1.045 g of CaO is added to 50.0 mL of water at 25.0 °C in a calorimeter, the temperature of the water increases to 32.3 °C.
Rus_ich [418]

Answer:

1.71 kJ/mol

Explanation:

The expression for the calculation of the enthalpy change of a process is shown below as:-

\Delta H=m\times C\times \Delta T

Where,  

\Delta H  is the enthalpy change

m is the mass

C is the specific heat capacity

\Delta T  is the temperature change

Thus, given that:-

Mass of CaO = 1.045 g

Specific heat = 4.18 J/g°C

\Delta T=32.3-25.0\ ^0C=7.3\ ^0C

So,  

\Delta H=1.045\times 4.18\times 7.3\ J=31.88713\ J

Also, 1 J = 0.001 kJ

So,  

\Delta H=0.03189\ kJ

Also, Molar mass of CaO = 56.0774 g/mol

Moles=\frac{Mass}{Molar\ mass}=\frac{1.045}{56.0774}\ mol=0.01863\ mol

Thus, Enthalpy change in kJ/mol is:-

\Delta H=\frac{0.03189}{0.01863}\ kJ/mol=1.71\ kJ/mol

8 0
3 years ago
Someone pls help with this
Anettt [7]
Question 3 is uniformitarianism
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5 0
3 years ago
Calculate the net change in enthalpy for the formation of one mole of nitric acid from nitrogen, hydrogen and oxygen from these
deff fn [24]
The formation of nitric acid from nitrogen, hydrogen, and oxygen can be written as,

     N₂ + H₂ + 3O₂ --> 2HNO₃

The net enthalpy of formation of nitric acid is calculated by,
   Hrxn = Hproduct - Hreactant

Since all the reactants are in their elemental forms, the simplified equation would be,

    Hrxn = Hproduct 

Substituting,

    Hrxn = (-186.81 kJ/mol)(2 mols)

<em>Answer: -372.42 kJ</em>

7 0
3 years ago
This unbalanced equation represents a chemical reaction:
inn [45]

Answer:

2

Explanation:

Pb(NO3)2 + 2NaI 2NaNO3 + PbI2

5 0
3 years ago
Read 2 more answers
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